Answer:
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Step-by-step explanation:
Answer:
y = 42x
Step-by-step explanation:
<span>So we want to rewrite the function v=8h^2 in terms of h so that it can represent the height of an object that is launched upward. So we take a square root: sqrt v= h*sqrt 8. Then we divide both sides of the equation with sqrt 8: h=(sqrt v)/sqrt 8=sqrt(v/8). So our function is: h=sqrt(v/8) or h=(1/2)*sqrt(v/2). </span>
Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
Yes. Examples: 1/1=1 2/4=2 1/2=0,5 1/0=?
