The classifications of the functions are
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
<h3>How to classify each function accordingly?</h3>
The categories of the functions are given as
- A vertical stretch
- A vertical compression
- A horizontal stretch
- A horizontal compression
The general rules of the above definitions are:
- A vertical stretch --- g(x) = a f(x) if |a| > 1
- A vertical compression --- g(x) = a f(x) if 0 < |a| < 1
- A horizontal stretch --- g(x) = f(bx) if 0 < |b| < 1
- A horizontal compression --- g(x) = f(bx) if |b| > 1
Using the above rules and highlights, we have the classifications of the functions to be
- A vertical stretch --- p(x) = 4f(x)
- A vertical compression --- g(x) = 0.65f(x)
- A horizontal stretch --- k(x) = f(0.5x)
- A horizontal compression --- h(x) = f(14x)
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Answer:
Step-by-step explanation:
Q1)
Use Phythogoras theorem:
Q2)
Apply phythogoras theorem:
Q3)
Apply phythogoras theorem again:
I have an attached an image for Question 2 for better understanding the length of DE in question equals 15 - 6 = 9
Answer:
i have the same question someone helppppppp
Step-by-step explanation:
Answer:
Number of offices to be cleaned to cover the cost of equipment =15
Cost of equipment =$.315 Cost of supplies =$.4 Charge per office =$.25
Number of offices to be cleaned to cover the cost of equipment =x
Then -25x − 4x =315
21x =315
x=315
21=15
Number of offices to be cleaned to cover the cost of equipment =15
