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Ronch [10]
3 years ago
14

Which term describes the degree to which a network can continue to function despite one or more of its processes or components b

reaking or being unavailable?
fault-tolerance

file tolerance

fault-line

file protection
Computers and Technology
1 answer:
liubo4ka [24]3 years ago
4 0

Answer:

the answer is fault tolerance

Explanation:

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Your computer has two basic types of software: system software and ________ software.
Elan Coil [88]
Hi!

Our computers will have system software and application software. Application software would be something like a game or just any general purpose app you've downloaded.

Hopefully, this helps! =)
5 0
4 years ago
A computing company is running a set of processes every day. Each process has its own start time and finish time, during which i
Helga [31]

Answer:

Above all else, let us show that this issue has the greedy choice property.

This implies that worldwide ideal arrangement can be gotten by choosing local ideal arrangements. Presently notice the following:

The global optimal solution of the issue requests us to track down the minimum number of times process_check module should be run.

It is likewise referenced that during each running interaction, process_check module should be called atleast once. Along these lines, the minimum possible number of process_check calls happens when process_check is made close to the quantity of the processes that are run.

Along these lines, we see that the global optimal solution is shaped by choosing optimal answer for the nearby advances.

Along these lines, the issue shows greedy choice property. Thus, we can utilize a greedy algorithm for this issue.

The greedy step in this calculation is to postpone the process_check as far as might be feasible. Thus, it should be run towards the finish of each interaction. So the following algorithm can be utilized:

Sort the cycles by utilizing the completion times.

Towards the finish of the 1st process in the arranged list, run the process_check module. Right now any process that is now running is removed the arranged rundown. The main interaction is additionally removed from the sorted list.

Now repeat stage 2, till all processes are finished.

In the above mentioned algorithm, the costliest advance is the step of sorting. By utilizing the optimal sorting algorithm, for example, merge sort, we can achieve it in O(n log n) asymptotic time.

Along these lines, this greedy algorithm additionally takes O(n log n) asymptotic time complexity.

5 0
3 years ago
Which of the following types of software applications would open a file
Mumz [18]
It’s C. An MP3 file is an audio/video file, so only a media player would be able to play this
8 0
4 years ago
Write a Python program that takes a file name as input and generates the following output: File size in bytes and KBs Time the f
Airida [17]

Answer:

See explaination

Explanation:

import os

import time

from stat import *

file = input("Enter file name: ")

details = os.stat(file)#stores statistics about a file in a directory

print("File size: ", details[ST_SIZE])#retreiving size

print("File last accessed time: ", time.asctime(time.localtime(details[ST_ATIME])))#access time

print("File last modified time: ", time.asctime(time.localtime(details[ST_MTIME])))#modified time

print("File creation time: ", time.asctime(time.localtime(details[ST_CTIME])))#creation time

print("First character: ", file[0])

print("Middle character: ", file[len(file) // 2])

print("Last character: ", file[len(file) - 1])

num_words = 0

num_lines = 0

f=open(file, "r")

lines = f.readlines()

for line in lines:

num_lines = num_lines + 1

num_words = num_words + len(line.split())#add no. of words in that line

print("Number of lines: ", num_lines)

print("Number of words: ", num_words)

8 0
3 years ago
The timer is running in the up mode with a period of 800 cycles. Channel 1 engages the output mode (Set/Reset) and sets its regi
Soloha48 [4]

Answer:

Explanation:

Part a)

_______________ ____________ _____________ ___

TAR | /\ \/ /\ \/ /\

|//////////|____________|____________|_____________|__________|

0 600 800 600 800 600

PWM Duty Cycle = 200/800 = 25%

Part b)  

______________ _________________ _________ _________________

TAR | \/ /\ \/ /\ \/

|//////////|_________|_________________|__________| _______________|

0 600 800 600 800 600

PWM Duty Cycle = 600/800 = 75%

7 0
3 years ago
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