Question

For f(x)=x/4-3 and g(x)=4x^2+2x-4 find (f+g)(x)

Answer 1

$f(x)=\dfrac{x}{4}-3=\dfrac{1}{4}x-3\\\\g(x)=4x^2+2x-4\\\\(f+g)(x)=f(x)+g(x)=\dfrac{1}{4}x-3+4x^2+2x-4\\\\=4x^2+\left(\dfrac{1}{4}x+2x\right)+(-3-4)=4x^2+2\dfrac{1}{4}x-7$