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Leona [35]
3 years ago
13

A=1/2h(B+b); A=45, B=4, b=5

Mathematics
1 answer:
klemol [59]3 years ago
4 0
Answer: h=10

Solving Steps:
45 = 1/2h x (4+5)
45 = 1/2h x 9
45 = 9/2h
10 = h
h = 10
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Each month Allison gets a $15 allowance and earns $100 working at the theater. She uses the expression 15x+100y to keep track of
Marizza181 [45]

Step-by-step explanation:

The expression for he earning of Allison and her allowance is as follows :

15x+100y

Part A

Variables are x and y. Coefficients are 15 and 100.

Part (B)

There are two terms in this expression. + is used to separate the terms. 15x and 100y are the terms.

Part (C) As $15 shows her earning from allowances. Hence, 15x shows allowance.

3 0
3 years ago
Starting at the same point, Joe and Anita go roller blading in opposite directions. If Joe roller blades at a speed of 4 mph, an
agasfer [191]

Answer:

They will be at a distance of 16 miles apart from each other.

Step-by-step explanation:

Both Joe and Anita start roller balding in opposite directions, and both of them have the same speed of 4 mph.

As they move oppositely in a straight line therefore, the distance between them will be the distance travelled by each of them's sum.

Distance covered by Joe in 2 hours= 8 miles

Distance covered by Anita in 2 hours= 8 miles

Therefore, the total distance from each other =16 miles

8 0
3 years ago
Help me out. good points the image shows​
Sphinxa [80]
To start off with you need to get math-way it will help out
5 0
2 years ago
Read 2 more answers
Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
  • \tan \theta = \frac{Side \: opposite \: to \: \theta}{Side \: adjacent \: to \: \theta}

<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

=> x = \frac{7}{0.27563....} = 25.39568..... ≈ 25.3

2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

Hypotenuse = 12

=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

=> x = 12 \times 0.73135.... = 8.77624.... ≈ 8.8

5) θ = 55°

Length of side adjacent to θ = x

Hypotenuse = 6

=> \cos 55 = \frac{x}{6}

=> \frac{x}{6} = 0.57357......

=> x = 6 \times 0.57357.... = 3.44145.... ≈ 3.4

6) θ = 73°

Length of side adjacent to θ = 8

Hypotenuse = x

=> \cos 73 = \frac{8}{x}

=> \frac{8}{x} = 0.29237......

=> x = \frac{8}{0.29237.....} = 27.36242..... ≈ 27.3

7) θ = 69°

Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

5 0
2 years ago
un frasco de jugo tiene una capacidad de 3/8 de litro ¿cuantos frascos se pueden llenar con cuatro litros y medio de jugo?
tangare [24]
Tenemos que

la capacidad del frasco es igual a 3/8 de litro
cuatro litros y medio es igual a decir 4 1/2 litros----> (4*2+1)/2----> 9/2 litros

realizamos una regla de tres
 si un frasco tiene capacidad para--------------> 3/8 litros
 X frascos-----------------------------------------> para 9/2 litros
X=(9/2)/(3/8)--------> 72/6-----> 12 frascos

la respuesta es
12 frascos
6 0
3 years ago
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