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Leona [35]
3 years ago
13

A=1/2h(B+b); A=45, B=4, b=5

Mathematics
1 answer:
klemol [59]3 years ago
4 0
Answer: h=10

Solving Steps:
45 = 1/2h x (4+5)
45 = 1/2h x 9
45 = 9/2h
10 = h
h = 10
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A telescope contains both a parabolic mirror and a hyperbolic mirror. They share focus ​, which is 46feet above the vertex of th
uranmaximum [27]

the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.

The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.

In terms of hyperbola, F1F2=2c, c=20.

The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.

Use formula c^2=a^2+b^2c

2

=a

2

+b

2

to find b:

\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}

(20)

2

=(18)

2

+b

2

,

b

2

=400−324=76

.

The branches of hyperbola go in y-direction, so the equation of hyperbola is

\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1

b

2

y

2

−

a

2

x

2

=1 .

Substitute a and b:

\dfrac{y^2}{76}- \dfrac{x^2}{324}=1

76

y

2

−

324

x

2

=1 .

7 0
3 years ago
In the number 409.21 what digit is in the ones place
Orlov [11]

Answer: The number before the decimal

Step-by-step explanation:

5 0
3 years ago
Ja'kniya and Alayjah are shopping at the Apple Store. Ja'kniya bought 4 screensavers and 3 Otterboxes for $29. Alayjah bought 6
Katarina [22]

Answer:  Each screensaver costs $2 and each Otterbox costs $7.

Step-by-step explanation:

Let x = Cost of each screensaver and y = cost of each Otterbox.

As per given, 4x+3y=29       (i)

6x +2y = 26  (ii)

Divide both sides of (i) by 2 and the multiply it by 3 on sides , we get

9x+3y=39    (iii)

Eliminate (i) from (iii) , we get

5x = 10

⇒ x = 2  [Divide both sides by 5]

Put value of x in (i), we get

4(2)+3y=29

⇒ 8+3y= 29

⇒ 3y= 21

⇒ y =7 [Divide both sides by 7]

Hence, Each screensaver costs $2 and each Otterbox costs $7.

7 0
3 years ago
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6 0
3 years ago
Which of the following conjectures is false?<br>Please give a counterexample!<br>Thank youuu
MakcuM [25]

Which of the following conjectures is false?

Solution: The false conjecture is:

J. The sum of two odd numbers is odd

Explanation:

F. The product of two even numbers is even.

For example: Let us take two even numbers 4 and 6.

The product of two even numbers is:

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Therefore, the product is also even number. Hence the conjecture is true.

G. The sum of two even numbers is even.

For example: Let us take two even numbers 4 and 6.

The sum of two even numbers is:

4+6 = 10

Therefore, the sum is also even number. Hence the conjecture is true.

H. The product of two odd numbers is odd.

For example: Let us take two odd numbers 3 and 5.

The product of two odd numbers is:

3\times5 = 15

Therefore, the product is also odd number. Hence the conjecture is true.

J. The sum of two odd numbers is odd.

For example: Let us take two odd numbers 3 and 5.

The sum of two odd numbers is:

3+5= 8

Therefore, the sum is not an odd number. Hence the conjecture is false.

6 0
3 years ago
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