A person can see the top of a building at an angle of 65°. The person is standing 50 ft away from the building and has an eye le
vel of 5 ft. How tall is the building to the nearest tenth of a foot?
1 answer:
Answer:
112.2ft
Step-by-step explanation:
As can be seen in the attached diagram, The top of the building is at C.
The distance from the man to the building is |BD| and the height of the man is |AB| where his eye level is at B.
We are required to find the height |CE| of the building.
Now |AB|=|DE|, (opposite sides of a rectangle).
Tan 65° = |CD|/59
|CD|=59 XTan65°=107.23
The height of the building |CE|=|CD|+|DE|=107.23+5=112.23ft
The height=112.2ft ( to the nearest tenth)
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Answer:
Since M1 has the higher probability of being in the desired range, we choose M1.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.
So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.
For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.
M1:
Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that
The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So
X = 1100
has a pvalue of 0.6915.
X = 900
has a pvalue of 0.0668
0.6915 - 0.0668 = 0.6247.
M1 has a 62.47% probability of being in the desired range.
M2:
M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that
X = 1100
has a pvalue of 0.7967.
X = 900
has a pvalue of 0.2033
0.7967 - 0.2033 = 0.5934
M2 has a 59.34% probability of being in the desired range.
Since M1 has the higher probability of being in the desired range, we choose M1.