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Gekata [30.6K]
3 years ago
15

What group of organic compounds is the main source of energy for living things

Biology
1 answer:
Rainbow [258]3 years ago
8 0
<span>What group of organic compounds is the main source of energy for living things</span>
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La destrucción experimental de proteínas presentes en la membrana plasmática afectará a procesos celulares, tales como la (el)
qaws [65]

Answer:

Ósmosis.

Explicación:

La destrucción experimental de proteínas presentes en la membrana plasmática afectará los procesos celulares, como la ósmosis, porque estas proteínas en la membrana plasmática son responsables del intercambio de materiales a través de la célula. Debido a la destrucción de proteínas, no se produjo la difusión de gases y materiales a través de la célula, lo que conduce a la muerte de la célula. La ósmosis es un proceso muy importante que permite a la célula difundir los materiales de desecho fuera de la célula y permite que los gases y la glucosa entren en la célula.

3 0
3 years ago
Inheritance patterns cannot always be explained by Mendel's models of inheritance. If a pair of homologous chromosomes fails to
soldier1979 [14.2K]

The question is incomplete as it does not have the options which are:

A) n+1; n+1; n-1; n-1

B) n+1; n-1; n; n

C) n+1; n-1; n-1; n-1

D) n+1; n+1; n; n

Answer:

Option-1

Explanation:

The laws of inheritance were concluded from the result of Mendel's experiment which is based on the fact that gametes are formed. Later research suggested that gametes are formed by the process of meiosis which takes place in two phases and recombination is a characteristic of Meiosis.

If during anaphase I of meiosis I, the alleles fails to separate that is nondisjunction takes place at anaphase I, Then the resulting daughter cells will have unequal distribution of chromosomes.

One daughter cell will receive 1 extra copy of the chromosome while another daughter cell will receive 1 less chromosome therefore ploidy level will be n+1 and n-1.

During meiosis II, 2 more daughter cells will be formed with the same ploidy level therefore in last the meiosis will result in 2 (n+1) and 2 (n-1) cell.

Thus, Option-1 is the correct answer.

4 0
4 years ago
A titratable group is in the active site of an enzyme and must be protonated for the enzyme to function. Assume that the group h
olya-2409 [2.1K]

Answer:

The correct option is 3. "At pH 6.5 the enyzme is 50% active"

Explanation:

For the titratable group to be protonated and cause the enzyme to be in the active state, it needs to have gained a hydrogen cation (H+). In order for that to happen, there must be enough hydrogen cations in the environment of the enzyme, and hence, an acidic pH is required in this case.

7 0
4 years ago
WILL GIVE 30 POINTS (by the way this is FLVS)
densk [106]

societal law is A statement about how things act in the natural world. the wire and electro magnet need to touch in question 2. a decrease in spee decreases kinetic energy. the test variable was the distance traveled by the scrunched paper.

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3 years ago
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C hdksjwkekeowkwhdjwiwk
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3 years ago
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