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Fantom [35]
4 years ago
7

Briefly describe the water cycle

Chemistry
2 answers:
Xelga [282]4 years ago
4 0
The water cycle is a cycle that makes water go in the sky and back on ground again. It has 3 main processes which are Condensation: water droplets collect on a cold surface and combine with humid air, Evaporation: the process of a liquid turning into a gas, and Precipitation: The process of water falling from the sky like; rain, snow, sleet, and hail.
Sergeu [11.5K]4 years ago
4 0
Precipitation is a vital component of how water moves through Earth’s water cycle, connecting the ocean, land, and atmosphere.
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if you replaced the tungsten filament of a typical incandescent bulb with an iron filament, would the emission spectrum be the s
Readme [11.4K]
<span>the electrons change their energy states and photons in visible spectrum (and infrared spectrum) are emitted.More the losses, more would be the light, but at the same time, more would be the heat generated.So this necessitates that the metal used should have high resistivity (and hence high losses), good thermmal conductivity and high melting point.

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4 0
4 years ago
The mass of solution is equivalent to the mass of the?
Maurinko [17]
A. Solution+ solvent
4 0
3 years ago
If you had 15 moles of Oxygen (O2), how many moles of water (H2O) would you be able to make?
larisa [96]

Answer:

30 moles of water will produced.

Explanation:

Given data:

Number of moles of O₂ react = 15 mol

Number of moles of water formed = ?

Solution:

Chemical equation:

2H₂ + O₂      →     2H₂O

Now we will compare the moles of water with oxygen.

                  O₂           :          H₂O

                   1             :            2

                   15           :           2×15 = 30 mol

30 moles of water will produced.

                   

5 0
3 years ago
the molar solubility of Zn(OH)2 is 5.7x 10^-3 mol/L at a certain temperature. Calculate the value of Ksp for Zn(OH)2 at this tem
Alex

Answer:

Ksp = 7.4x10⁻⁷

Explanation:

Molar solubility of a substance is defined as the amount of moles of that can be dissolved per liter of solution.

Ksp of Zn(OH)₂ is:

Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻

Ksp = [Zn²⁺] [OH⁻]²

And the molar solubility, X, is:

Zn(OH)₂(s) ⇄ Zn²⁺ + 2OH⁻

                 ⇄ X + 2X

<em>Because X are moles of substance dissolved.</em>

<em>Ksp = </em>[X] [2X]²

Ksp = 4X³

As molar solubility, X, is 5.7x10⁻³mol/L:

Ksp = 4X³

Ksp = 4 (5.7x10⁻³mol/L)³

<h3>Ksp = 7.4x10⁻⁷</h3>

5 0
3 years ago
Based on your measured potential for this cell and the literature value for the standard reduction potential for the ag/agcl ref
Marta_Voda [28]
I have attached an image that shows the measured cell potentials, and this question specifically refers to cell #4 with the following reaction:

Cu²⁺(aq) + 2Ag(s) → Cu(s) + 2Ag⁺(aq)    Ecell = 0.137 V

We can separate this reaction into its two half reactions to identify the anode and cathode:

Cathode: Cu²⁺ + 2e⁻ → Cu    E° = 0.34 V
Anode: Ag → Ag⁺ + 1e⁻         E° = 0.22 V

The formula for cell potential is:

Ecell = Ecathode - Eanode

We are asked to solve for the cell potential of the Cu²⁺/Cu electrode using the standard Ag/AgCl electrode potential and the measured potential:

0.137 V = Ecathode - 0.22 V
Ecathode = 0.137 + 0.22
Ecathode = 0.357 V

Now we can compare this value for the Cu²⁺/Cu electrode with the standard hydrogen electrode:

Ecell = 0.357 V - 0 V
Ecell = 0.357 V

We found a value of 0.357 V, however, the literature value is 0.34 V and now we can solve for the % error in our experimental value:

% error = ([experimental - theoretical]/[theoretical]) x 100%

% error = ((0.357 - 0.34)/0.34) x 100%

% error = 5 %

The experimental electrode potential for the Cu²⁺/Cu electrode was 0.357 V which has a 5% error compared to the literature value.

4 0
4 years ago
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