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viktelen [127]
3 years ago
9

When a warm air mass is caught between two cooler air masses and the thicker cold air masses move underneath the thinner warm ai

r mass and push it upward is what type of weather front?
Chemistry
2 answers:
almond37 [142]3 years ago
6 0
An occluded front forms when a warm air mass is caught between two cooler air masses. The warm air mass is cut ofl or occluded' from the ground. The occluded warm front may cause clouds and precipitation. A swirling center of low air pressure is called a cyclone.
amid [387]3 years ago
6 0
When a warm air mass is caught between two cooler air masses and the thicker cold air masses move underneath the thinner warm air mass and push it upward. Occluded front symbol – The directions that the bumps face is the direction the front is moving.
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Answer:   17 (a) 360,000 ms         18 (a) 0.245 s

                     (b) 4.800 kg                   (b) 500 cm

                     (c) 560.0 dm                  (c) 68.00 m

                     (d) 72,000 mg                (d) 0.025 Mg

<u>Explanation:</u>

Use the following table.  Note the direction you are going to:

Right means move decimal to the right. Left means move decimal to the left.

               \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

**********************************************************************************************

17(a) 360 s to ms                                                        o       →         →        →o

                            \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the right   -->   360_ _ _.

Fill in the blanks with zeroes   --> 360,000

  (b) 4800 g to kg                            o←    ←     ←         o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the left   --> 4.<u>8</u> <u>0</u> <u>0</u>

<u />

 (c) 5600 dm to m                                                       o←     o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 1 place to the left   --> 560. <u>0</u>

<u />

 (d)  72 g to mg                                                         o         →        →        →o

                            \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the right   --> 72 _ _ _.

Fill in the blanks with zeroes   -->     72,000

***********************************************************************************************

18 (a) 245 ms to s                                                       o←       ←       ←        o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the left -->   . <u>2</u> <u>4</u> <u>5</u>

     (b) 5 m to cm                                                        o        →        →o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 2 places to the right   -->   5 _ _.

Fill in the blanks with zeroes   -->    500

      (c) 6800 cm to m                                                 o←      ←        o

                             \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 2 places to the left   -->   68. <u>0</u> <u>0 </u>

<u />

    (d)  25 kg to Mg    o←    ←    ←    o

                            \boxed{\begin{array}{c|c|c|c|c|c|c|c|c|c}Mega&x&x&kilo&x&deka&unit&deci&centi&milli\\M\_\_&&&k\_\_&&dk\_\_&\_\_\_&d\_\_\)&c\_\_&m\_\_\end{array}}

Move the decimal 3 places to the left -->   . _ 25

Fill in the blanks with zeroes  -->   .025

6 0
4 years ago
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