We want to determine the domain of
![{y=3 \cdot 2^{-x}=3 \cdot ({2^{-1}})^x=3 \cdot ({ \frac{1}{2}})^x](https://tex.z-dn.net/?f=%7By%3D3%20%5Ccdot%202%5E%7B-x%7D%3D3%20%5Ccdot%20%28%7B2%5E%7B-1%7D%7D%29%5Ex%3D3%20%5Ccdot%20%28%7B%20%5Cfrac%7B1%7D%7B2%7D%7D%29%5Ex)
any function of the form
![y=f(x)=a \cdot b^x](https://tex.z-dn.net/?f=y%3Df%28x%29%3Da%20%5Ccdot%20b%5Ex)
is called an "exponential function",
the only condition is that b is positive and different from 1, and a is a nonzero real number.
The domain of such functions is all real numbers.
That is for any x, the expression <span>3(2^-x) "makes sense".
Answer: </span><span>The domain is all real numbers</span>
Minimum value is equal to x=8, y=-4First find the derivative of the original equation which equals= d/dx(x^2-16x+60) = 2x - 16at x=8, f'(x), the derivative of x equals zero, so therefore, at point x = 8, we have a minimum value.Just plug in 8 to the original equation to find the answer for the minimum value.
They are corresponding angles. Corresponding angles have equal measures.
Answer
The answer to your question is 2 x 2 x 5 x 5 or 2² 5²
Step-by-step explanation:
Process
1.- To find the prime factors of a number, we must divide the number by prime numbers like 2, 3, 5, 7, 11, etc. starting from the lowest number.
100 2
50 2
25 5
5 5
1
Then 100 = 2 x 2 x 5 x 5 or 2² 5²