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2 years ago

Lucy has 1/5 of a pound of chocolates. She would like to make 4 gift bags with chocolates for her teachers.

Mathematics

1 answer:

Lapatulllka [165]2 years ago

3 0

Answer:

0.05 pound of chocolate per gift bag or 1/20 pound of chocolate per gift bag

Step-by-step explanation:

1/5 divided by 4

=0.05 pound of chocolate per gift bag or 1/20 pound of chocolate per gift bag

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<h3><em><u>Hope this helped!! </u></em></h3>

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Perform the division and leave the result in trigonometric form.

Anettt [7]

Answer:

$\frac{1}{2}$ ( cos40° + isin40°)

Step-by-step explanation:

To divide

$\frac{r_{1(cosx_{1}+isinx_{1}) } }{r_{2}(cosx_{2}+isinx_{2}) }$

= $\frac{r_{1} }{r_{2} }$ [ cos(x₁ - x₂) + isin(x₁ - x₂)

Given

$\frac{2(cos90+isin90}{4(cos50+isin50)}$

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3 years ago

On the 1st January 2014 Carol invested some money in a bank account.

Ghella [55]

Answer:

$\large \boxed{\text{\pounds 23 360.00}}$

Step-by-step explanation:

The formula for the accrued amount from compound interest is

$A = P \left(1 + \dfrac{r}{n}\right)^{nt}$

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:

r = 0.025

$\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}$

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

$\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}$