Input Data :
Point 1 ( x A , y A ) = (-6, -2)
Point 2 ( x B , y B ) = (1, -6)
Objective :
Find the distance between two given points on a line.
Formula :
Distance between two points = √ ( x B − x A )2 + ( y B − y A ) 2
Solution :
Distance between two points = √ ( 1 - -6 ) 2 + ( − 6 − − 2 ) 2
= √ 7 2 + ( − 4 ) 2
= √ 49 + 16
= √ 65 = 8.0623
Distance between points (-6, -2) and (1, -6) is 8.0623
Or 8!!
Best of luck!!
#readmore
Hello!
We can begin by solving for c₃ given the equations:
c₃ = 3c₂ + 2c₁ - 2
c₃ = 3(2) + 2(4) - 2
Simplify:
c₃ = 6 + 8 - 2 = 12
We can now find the subsequent terms:
c₄ = 3(12) + 2(2) - 2 = 38
c₅ = 3(38) + 2(12) - 2 = 136
You can start by subtracting different equations from each other.
3x + 2y + 3z = 1
subtract
3x + 2y + z = 7
2z = -6
divide by 2
z = -3
add the following two expressions together:
3x + 2y + z = 7
3x + 2y + 3z =1
6x + 4y + 4z = 8
subtract the following two expressions:
6x + 4y + 4z = 8
5x + 5y + 4z = 3
x - y = 5
^multiply the whole equation above by 3
3x - 3y = 15
subtract the following two expressions:
3x - 3y = 15
3x + 2y = 10
-5y = 5
divide each side by -5
y=-1
take the following expression from earlier:
x - y = 5
substitute y value into above equation
x - - 1 = 5
2 negatives make a positive
x + 1 = 5
subtract 1 from each side
x = 4
Therefore x = 4, y = -1, z = -3
I checked these with all 3 equations and they worked :)
(it's quite complicated, comment if you don't understand anything) :)
