The point-slope equation of a line that cointains the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
so
point (-2,3) and slope -4
y-3=-4(x-(-2))
y-3=-4(x+2) is da equation
Times it bye 4 thin subtract bye 6
9+10=?
9 = 3x3
10= 5x2
3 (from 3x3) x 5 (from 5x2) = 15
3 (from 3x3) x 2 (from 5x2) = 6
15+6=21
Therefore 9+10=21
Y=5/2x+5 because the slope is 5/2 and the y-intercept is 5
