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3 years ago

13

A farmer wants to spray 3 gallons of pesticide equally on 10 farm plots. how many gallons of pesticide should he use for each pl

ot?

1 answer:

photoshop1234 [79]3 years ago

7 0

3 gallons on 10 things

Here, we have less things to be distributed than the number of things you distribute to.

Thus: 3/10 gallons.

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A rectangle has a width of 5 meters and a length of 7 meters. A similar rectangle has a width of 15 meters. What is the length o

JulijaS [17]

I believe 21 because 5×3 is 15 so 7×3=21

6 0

3 years ago

Read 2 more answers

how do you solve y=x+4 and y=-2x+1 using the subsituation method and show work and please give me the correct answer

SIZIF [17.4K]

Answer:

(-1,3)

Step-by-step explanation:

so y=x+4 and y=-2x+1

obviously, y=y

so that means that x+4 is equal to -2x+1

let's use that

y=x+4,y=-2x+1

y=y

x+4=-2x+1

x+2x=1-4

3x=-3

x=-1

y=x+4

y=(-1)+4

y=3

(-1,3)

6 0

3 years ago

THIS IS FOR 27 POINTS!!!<br> EXPLAIN PLEASE!!!!<br> Solve -9(2+a) + 4(2a+9)=11

Sindrei [870]

So,

First you have to distribute the numbers outside of the parentheses (you multiply them with the numbers inside of the parentheses

-18+(-9a) + 8a +36=11
Then collect like terms
18-1a =11
-18 -18
---------------------
-1a=-7
Divide both sides by -1
a=7

8 0

3 years ago

Read 2 more answers

Determine whether the relation describe c as a function of w.

Delicious77 [7]

Answer:

Function:

c = f(w) = 0.49, 0 < w ≤ 1

= 0.70, 1 < w ≤ 2

= 0.91, 2 < w ≤ 3

Step-by-step explanation:

Yes, the relation described can be interpreted as a function.

Here, c is the cost of a mail letter. c depends upon w, which is the weights of the mail letter.

As described in the question, the relation can be expressed as a function.

c can be expressed as a function of w in the following manner:

c(cost of mail) = f(w), where w is the independent variable and c is the dependent variable

c = f(w) = 0.49, 0 < w ≤ 1

= 0.70, 1 < w ≤ 2

= 0.91, 2 < w ≤ 3

where, c is in dollars and w is in ounces.

5 0

4 years ago

6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the

MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

$a_1$ the horizontal distance between the first observer and the ballonist

$a_2$ the horizontal distance between the second observer and the ballonist

$\alpha _1$ and $\alpha _2$ the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

$S=a*h$ (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

$S=S_1+S_2$ (equation 2)

$S_1=a_1*h$

But we can write $S_1$ in terms of $\alpha _1$ , like this:

$\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}$

And for $S_2$ will be the same:

$S_2=\frac{h^{2} }{\tan(\alpha _2)}$

Replacing in the equation 2:

$S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})$

And replacing in the equation 1:

$h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}$

So, we can replace all the known data in the last equation:

$h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft$

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0

3 years ago