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Citrus2011 [14]
3 years ago
5

Simplify this algebraic expression. y-3/3+12

Mathematics
1 answer:
Alchen [17]3 years ago
7 0
Y-13. 3/3=1. 1+12=13. you can’t combine unlike terms so the answer is y-13.
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Expanded -8(-2x-5)<br> please give answer
nika2105 [10]

Answer:

-80

Step-by-step explanation:

We have to do the parentheses first because it's part of PEDMAS.

-2x-5= 10

Next, we take 10 times -8

-8 x 10= -80

There you go! Hope this helps!

8 0
3 years ago
Read 2 more answers
 Solve each system by graphing.
Kryger [21]

9514 1404 393

Answer:

  (x, y) = (4, -4)

Step-by-step explanation:

A graphing calculator makes graphing very easy. The attachment shows the solution to be (x, y) = (4, -4).

__

The equations are in slope-intercept form, so it is convenient to start from the y-intercept and use the slope (rise/run) to find additional points on the line.

The first line can be drawn by staring at (0, -2) and moving down 1 grid unit for each 2 to the right.

The second line can be drawn by starting at (0, 2) and moving down 3 grid units for each 2 to the right.

The point of intersection of the lines, (4, -4), is the solution to the system of equations.

3 0
3 years ago
Tyler answered 26 of 40 test questions correctly. What percent did he answer correctly?
Keith_Richards [23]

Answer:

65%

Step-by-step explanation:

26/40

5 0
3 years ago
Read 2 more answers
2. Solve the<br> triangle.<br> a = 12, b = 22, C = 95°
djyliett [7]

this is the answer to this question - Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?

Answer:

Reasons:

The given parameters are;

Distance between the two stations = 146 miles

Location of the weather balloon from the Western station = N35°E

Location of the weather balloon from the Eastern station = N23°E

The location of the station = On the equator

Required:

The distance of the balloon from the Western station

Solution:

- The angle formed between the horizontal, and the line from the Western station

to the balloon = 90° - 35° = 55°

- The angle formed between the horizontal, and the line from the Eastern station

to the balloon = 90° + 23° = 113°

The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°

By sine rule,

Distance from balloon to western station = 146/sin(12 dg) = Distance from balloon to western station/sin(113 dg)

Therefore;

Distance from balloon to western station = 146/sin(12 dg) x sin(113 dg) ~ 646.4

Step-by-step explanation:

7 0
2 years ago
Which set of statements would describe a parallelogram that can always be classified as a rhombus? I. Diagonals are perpendicula
trasher [3.6K]

Answer:

1. I, II,

Step-by-step explanation:

<em>I. Diagonals are perpendicular bisectors of each other  </em>

Yes, because 4 sides are congruent so it makes the two diagonals perpendicular bisectors

<em>II. Diagonals bisect the angles from which they are drawn </em>

Yes, That is the property of the diagonal!

<em> III. Diagonals form four congruent isosceles right triangles. </em>

No, only two pairs of right triangles are congruent and sometime the side of each pair are different to each other.

Hence, we choose I and II

4 0
3 years ago
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