(5x+3y) - (2x-7y) +8x

Autos de F 1. En un circuito de Australia, Hamilton hizo el récord de vuelta. Si lo normal a 240km/h para completar el circuito

olga2289 [7]

Answer:

Tenía que hacerlo en menos de 2 minutos a más de 240 km/h

Step-by-step explanation:

La velocidad normal dada para completar el circuito de 6.000 metros = 240 km/h

El tiempo normal que se tarda en completar el circuito de 6000 metros = 2 minutos

Dado que Hamilton estableció el récord de vuelta, el tiempo que tuvo que hacer para recorrer el récord de vuelta es de 6000 metros en menos de 2 minutos

La velocidad media con la que lo hizo es de más de 240 km/h.

6 0

2 years ago

Given P(E)= 0.24 and P(FnE)= 0.17, find P(F| E). Round the answer to the nearest hundredth. A. 029 B. 0.40 C. 0.71 D. 1.41

romanna [79]

Given P(E) = 0.24 and P(F ∩ E) = 0.17

It says to find conditional probability of F given E has occurred.

We know the formula of conditional probability is given by :-

P(F ║ E) = $\frac{P(E\;and\; F)}{P(E)}$

P(F ║ E) = $\frac{0.17}{0.24}$ = 0.708333

P(F ║ E) = 0.71

Hence, option C i.e. 0.71 is the final answer.

7 0

2 years ago

Rebecca collected data from a random sample of 1200 homeowners in her state asking whether or not they use electric heat. Based

larisa [96]

Hi,

The answer is c. The sample is biased.

This is because the sample is taken on a single state, an Rebecca reports a statistic about the nation. Her data contains information only of her state. If she lives in a very cold state, there is probably more homeowners using electric heat than in a hot state.

6 0

2 years ago

Find the surface area of the solid generated by revolving the region bounded by the graphs of y = x2, y = 0, x = 0, and x = 2 ab

Nikitich [7]

Answer:

See explanation

Step-by-step explanation:

The surface area of the solid generated by revolving the region bounded by the graphs can be calculated using formula

$SA=2\pi \int\limits^a_b f(x)\sqrt{1+f'^2(x)} \, dx$

If $f(x)=x^2,$ then

$f'(x)=2x$

and

$b=0\\ \\a=2$

Therefore,

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+(2x)^2} \, dx=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx$

Apply substitution

$x=\dfrac{1}{2}\tan u\\ \\dx=\dfrac{1}{2}\cdot \dfrac{1}{\cos ^2 u}du$

Then

$SA=2\pi \int\limits^2_0 x^2\sqrt{1+4x^2} \, dx=2\pi \int\limits^{\arctan(4)}_0 \dfrac{1}{4}\tan^2u\sqrt{1+\tan^2u} \, \dfrac{1}{2}\dfrac{1}{\cos^2u}du=\\ \\=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0 \tan^2u\sec^3udu=\dfrac{\pi}{4}\int\limits^{\arctan(4)}_0(\sec^3u+\sec^5u)du$

Now

$\int\limits^{\arctan(4)}_0 \sec^3udu=2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17})\\ \\ \int\limits^{\arctan(4)}_0 \sec^5udu=\dfrac{1}{8}(-(2\sqrt{17}+\dfrac{1}{2}\ln(4+\sqrt{17})))+17\sqrt{17}+\dfrac{3}{4}(2\sqrt{17}+\dfrac{1}{2}\ln (4+\sqrt{17}))$

Hence,

$SA=\pi \dfrac{-\ln(4+\sqrt{17})+132\sqrt{17}}{32}$

3 0

2 years ago

You collect a total of $75 in donations from three people. The three donations are in the ratio 4 to 4 to 7. How much is each of

worty [1.4K]

Each smaller donation was for $20 The largest donation was $15 greater than the smaller donation. First, determine the size of each donation. Since they are in a ratio of 4:4:7, it's easiest to add the ratios together (4+4+7) = 15. Then divide the total donation by that sum (75/15) = 5. Finally, multiply 5 by each of the ratios. 5 * 4 = 20, 5 * 4 = 20, and 5 * 7 = 35 So the 2 smaller donations were $20 each, and the largest donation was for $35. The largest donation was $35 - $20 = $15 larger than one of the smaller donations.

7 0

2 years ago