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Alex
2 years ago
6

Kendra has 4 necklaces, 7 bracelects, And 5 rings.Draw a model to show the ratio that compares rings to bracelets

Mathematics
1 answer:
xxMikexx [17]2 years ago
7 0
Ratio from rings to bracelets: 5:7

Let m=shaded square and y= clear square
mmmmmyyyyyyy
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Solve the equation<br> 4-t=3(t-1)-5
STALIN [3.7K]

Answer:

t=3

Step-by-step explanation:

4-t=3t-3-5

4-t=3t-8

+1

4=4t-8

+8

12=4t/4

5 0
3 years ago
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5(x+7)+2(y-1)when x=7 and y=2
balu736 [363]

Answer: 72

Step-by-step explanation:

First plug in 7 for x

5(14)

Then multiply

70

Next plug 2 in for y

2(1)

Multiply

2

Lastly, add 70 and 2 together.

72.

Hope this helps.

5 0
3 years ago
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Someone PLEASE help me!!!!!<br> Evaluate -/3/
Veseljchak [2.6K]

if / means absolute value, then the answer is -3. The absolute value of 3 is 3, then you take the negative value of it, which is -3.


Btw, the absolute sign is ||, not //.


5 0
3 years ago
A rectangular area is to be fenced in with 300 feet of chicken wire. find the maximum area that can be enclosed.
GarryVolchara [31]
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.

2(x+y) = 300
x+y = 150
y = 150-x

A=x(150-x) <--(substitution)

The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150

So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.

A=75(150-75)
A=75*75
A=5625

So the maximum area that can be enclosed is 5625 square feet.
6 0
3 years ago
How do you find fh if ️fgh ~ ️kjh​
Lostsunrise [7]
What is that ? are you joking ?
5 0
2 years ago
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