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lianna [129]
3 years ago
10

The mass of a silver bracelet is 2.5 gram, it occupies a volume of 48cm3, what is its density?​

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

The answer is

<h2>0.052 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 2.5 g

volume = 48 cm³

The density is

density =  \frac{2.5}{48}   \\  = 0.052083333...

We have the final answer as

<h3>0.052 g/cm³</h3>

Hope this helps you

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I am having some trouble figuring out how to approach the following problem: A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is ti
Tanya [424]
<span>We look at the end of the day:

n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
M [OH-] = Kb * [NH3] = 0.070652*1.8*10^(-5) = 1.27174 x 10^(-6)
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4 0
3 years ago
How are molecules built?
RoseWind [281]
Bonding I'm guessing
6 0
3 years ago
Identify the most acidic hydrogens in each of the following molecules. Give the structure of the enolate ion arising from deprot
san4es73 [151]

Answer:

See explanation below (Brainlist please)

Explanation:

First of all, we need to understand what is an acidic hydrogen.

An acidic hydrogen, is the atom of hydrogen which is more propense to undergo an acid base reaction, and form a stable ion or molecule in the process.

In other words, is the hydrogen that is more vulnerable to get substracted in an acid base reaction to form another compound.

Knowing this information, gives us an idea of how a molecule can be formed and which kind of compound is formed.

Now, in this question, we have 5 molecules. Each of them is either a ketone or aldehyde, so this mean that we have the carbonile group (C = O), which means that is easier to identify the acidic hydrogen. This is because the Carbonile group is an attractor group, so, it will attract the charges by inductive effect (in some cases by resonance), and the molecule is more stable.

This can be shown by drawing the enolate ion that is formed once the molecule undergo the acid base reaction. As it's an enolate form that we are looking for, then it means that the ketone or aldehyde is undergoing an electrofilic attack with a base. This base will substract the most acidic hydrogen to form a better and stable enolate. The acidic hydrogen and the enolate form can be seen in the attached picture.

a) In the case of acetaldehyde, the most acidic will be the hydrogen of carbon 2, because the hydrogen from the carbonile, once it's substracted, the charge of the carbon cannot be stabilized by resonance. Carbon 2 hydrogens, can do this job easily.

b) Propanal happens something similar to acetaldehyde, the terminal hydrogen cannot be substracted, and carbon 3, once the hydrogen is gone, the negative charge cannot be stabilized by resonance, so hydrogens of carbon 2 can do this.

c) in the case of acetone, is easier to look because we only have the C = O between two methyl group, so you can use either carbon 1 or 3 to do the job.

d) 4 heptanone the most acidic hydrogen would be carbon 3 or 5, because they are closer to the C=O and the ion can be stabilized by resonance.

e) Finally in ciclopentanone, the most acidic hydrogen would be carbon 2 or 5.

See picture for a better understanding.

Hope it helps.

7 0
3 years ago
Develop a message for the owners of cars in villages explaining why the vehicles should be kept well even if they are spoiled, w
Lera25 [3.4K]
<h2>Answer:</h2>

<h3>#Carry On Learning</h3>

<h2>Explanation:</h2>

<h3>I hope It's Help</h3>

3 0
3 years ago
Find the volume of 3.011x1023 molecules of O2 at STP.
lord [1]

Answer:

6.022 x 1023 molecules = 1 Mole O2 = 22.4L

3.022 x 1023 molecules = 1/2 Mole O2 = 11.2L

The answer is 11.2 Litres

Explanation:

8 0
2 years ago
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