1. Berkelium(Berkeley, CA) 2. Dubnium(Dubna, Russia) 3. Darmstaditum (Darmstadt, Germany) 4. Erbium(Ytterby, Sweden) 5. Strontium(Strontian, Scotland) 6. Terbium(Ytterby, Sweden) 7. Yttebium(Ytterby, Sweden) 8. Yttrium(Ytterby, Sweden)
Answer:
440mt/p gallons
Explanation:
We are told that one gallon of paint covers an area of p square feet. Knowing this then, the question becomes how much paint is needed to cover a stripe that is t inches wide and m miles long.
Let us first use the dimensions of the stripe to find how much area that is in square feet. A stripe is rectangular so we will calculate the area as follows:
Area of stripe = width x length
= t inches x m miles (we need to convert both to feet)
= (t inches x 1 ft/12 inches) x (m miles x 5280 ft/1 mi)
=440mt square feet
ow we can find out how much paint will be needed by using ratios
p square feet : 1 gallon
440mt square feet : x
x = 440mt/p gallons
The mass of water produced by the reaction of the 23 g of 
is 13.8 g.
The given chemical reaction;
In the given compound above, we can deduce the following;
- molecular mass of = 28 + (2 x 16) = 60 g
- molecular mass of
= 2(18) = 36 g
60 g of --------- 36 g of water
23 g of ------------- ? of water
Thus, the mass of water produced by the reaction of the 23 g of is 13.8 g.
- <em>"Your question is not complete, it seems to be missing the following information";</em>
In the reaction of the given compound, , what mass of water (in grams) is produced by the reaction of 23.0 g of SiO2?
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