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anastassius [24]
3 years ago
8

Matter that flows to fit its container includes ?

Chemistry
2 answers:
Vlad1618 [11]3 years ago
8 0
This includes liqued

baherus [9]3 years ago
6 0
Thsi includes liquids
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Which statement is true about the ionic size of the elements in a group as one moves from top to bottom in that group?
nekit [7.7K]

Answer:

Ionic size increases from top to bottom within the group.

Explanation:

  • Ions are formed when neutral atoms of elements gain or lose electron(s).
  • The ionic radius is the distance from the nucleus of an ion to the outermost energy level.
  • The ionic size or radius increases down the group as the number of energy level increases.
  • Therefore, an ion of an element lower in the group will be larger than the ion of an element higher in the group.
  • For example, an ion of potassium, K+, is larger in size compared to the ion of sodium, Na+ since K+ has more energy levels than Na+.
8 0
3 years ago
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Explain why argon is used in tungsten filament lamps​
PSYCHO15rus [73]

Answer:

Because it helps the filament from decaying

5 0
3 years ago
A solution is prepared by dissolving 10.0 g of NaBr and 10.0 g of Na2SO4 in water to make a 100.0 mL solution. This solution is
Colt1911 [192]

Answer:

M_{Na^+}=1.36M

M_{Br^-}=1.58M

Explanation:

Hello,

At first, it turns out convenient to compute the total moles of sodium that will be dissolved into the solution by considering the added amounts of sodium bromide and sodium sulfate:

n_{Na^+}=n_{Na^+,NaBr}+n_{Na^+,Na_2SO_4}\\n_{Na^+,NaBr}=10.0gNaBr*\frac{1molNaBr}{103gNaBr}*\frac{1molNa^+}{1molNaBr}=0.0971molNa^+\\n_{Na^+,Na_2SO_4}=10.0gNa_2SO_4*\frac{1molNa_2SO_4}{142gNa_2SO_4}*\frac{2molNa^+}{1molNa_2SO_4} =0.141molNa^+\\n_{Na^+}=0.0971molNa^++0.141molNa^+\\n_{Na^+}=0.238molNa^+

Once we've got the moles we compute the final volume via:

V=100.0mL+75.0mL=175.0mL*\frac{1L}{1000mL}=0.1750L

Thus, the molarity of the sodium atoms turn out into:

M_{Na^+}=\frac{0.238mol}{0.1750L} =1.36M

Now, we perform the same procedure but now for the bromide ions:

n_{Br^-}=n_{Br^-,NaBr}+n_{Br^-,AlBr_3}\\n_{Br^-,NaBr}=10.0gNaBr*\frac{1molNaBr}{103gNaBr}*\frac{1molBr^-}{1molNaBr}=0.0971molBr^-\\n_{Br^-,AlBr_3}=0.0750L*0.800\frac{molAlBr_3}{L} *\frac{3molBr^-}{1molAlBr_3}=0.180molBr^- \\n_{Br^-}=0.0971molBr^-+0.180molBr^-\\n_{Br^-}=0.277molBr^-

Finally, its molarity results:

M_{Br^-}=\frac{0.277molBr^-}{0.1750L}=1.58M

Best regards.

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Which TWO are most likely to form a compound?<br> C<br> Mg<br> S<br> Ar
lbvjy [14]
Answer is Mr and S as MgS ..
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The natural tendence of an object to resist change in its state of motion is:
melisa1 [442]

Inertia. Inertia is the natural tendency of bodies to remain in their states of either rectilinear or resting motion.

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