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inna [77]
3 years ago
5

Considering , will F ever equal zero?

Physics
2 answers:
Kamila [148]3 years ago
4 0
No it will not because F will equal 3 not 0

Tema [17]3 years ago
3 0

Answer:

no

Explanation:

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Why a body in uniform velocity is zero acceleration ?​
seropon [69]
Uniform velocity means no Net force and therefore no acceleration. Acceleration only happens when the velocity changes.
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3 years ago
A. What is the coefficient of kinetic friction?
Andrews [41]

Explanation:

Coefficient of kinetic friction is the resistive force that opposes the motion of a body as it moves and is in contact with another body.

It is found by dividing the frictional force by the normal force.

  • Friction is a force that opposes motion.
  • Static friction is for bodies that are not in motion
  • Kinetic friction is for moving bodies.
7 0
3 years ago
Can anybody help me solve this problem? Thank you so much!
ser-zykov [4K]
Please ignore my comment -- mass is not needed, here is how to solve it. pls do the math

at bottom box has only kinetic energy
ke = (1/2)mv^2
v = initial velocity
moving up until rest work done = Fs
F = kinetic fiction force = uN = umg x cos(a)
s = distance travel = h/sin(a)
h = height at top
a = slope angle
u = kinetic fiction
work = Fs = umgh x cot(a)
ke = work (use all ke to do work)
(1/2)mv^2 = umgh x cot(a)
u = (1/2)v^2 x tan (a) / gh
4 0
2 years ago
A running mountain lion can make a leap 10.0 mlong, reaching a maximum height of 3.0 m. What is the speed of the mountain lion j
nika2105 [10]

To solve this problem we will use the kinematic equations of descriptive motion of a projectile for which both the height reached and the distance traveled are defined. From this type of movement the lion reaches a height (H) of 3m and travels a horizontal distance (R) of 10 m. Mathematically the equations that describe this movement are given as,

H = \frac{v_0^2sin^2\theta}{2g}

R = \frac{v_0^2 sin 2\theta}{g}

Dividing the two equation we have that

\frac{H}{R}=\frac{\frac{v_0^2sin^2\theta}{2g}}{\frac{v_0^2 sin 2\theta}{g}}

\frac{H}{R}= \frac{sin^2\theta}{2}*\frac{1}{sin2\theta}

\frac{H}{R}= \frac{sin^2\theta}{2}*\frac{1}{2sin\theta cos\theta}

\frac{H}{R}= \frac{1}{4} \frac{sin\theta}{cos\theta}

\frac{H}{R}= \frac{1}{4} tan\theta

Substituting values of H and R, we get

\frac{3}{10} = \frac{1}{4} tan\theta

\theta = tan^{-1} \frac{12}{10}

\theta = 50.2\°

Substituting the value of \theta in equation we get,

H = \frac{v_0^2sin^2\theta}{2g}

v_0^2 = \frac{H 2g}{sin^2\theta}

v_0^2 = \frac{3*2*9.8}{sin^2(50.2)}

v_0^2 = 99.62

v_0 = \sqrt{99.62}

v_0 = 9.98m/s

Therefore the speed of the mountain lion just as it leaves the ground is 9.98m/s at an angle of 50.2°

5 0
2 years ago
What's is the power output of an engine that does 60000 J of work in 10 seconds​
ad-work [718]
A: 6,000 watts

Equation for power: P= work / time
8 0
3 years ago
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