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UNO [17]
3 years ago
8

A car traveling at 26.8m/s hits the brakes to slow down before turning into a neighborhood. Determine how fast it is going after

slowing down at a rate of -8.2m/s2 for 14.3seconds.
Physics
1 answer:
AURORKA [14]3 years ago
6 0

Answer:

The speed of the car after the break was applied is  90.46 m/s

Explanation:

Given;

initial velocity of the car, u = 26.8 m/s

accelertation of the car, a = -8.2 m/s²

time of motion, t = 14.3 s

final velocity, v = ?

Apply the following kinematic equation;

v = u + at

v = 26.8 + (-8.2 x 14.3)

v = 26.8 -  117.26

v = -90.46 m/s

magnitude of the final velocity = 90.46 m/s

Therefore, the speed of the car after the break was applied is  90.46 m/s

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You need to repair a gate on the farm. The gate weighs 100 kg and pivots as indicated. A small diagonal bar supports the gate an
tekilochka [14]

Answer:

The force is  F = 3920 \ N

Explanation:

The diagram for this question is shown on the first uploaded image

   From the question we are told that

          The weight of the gate is G  =  100\  kg

 

The vertical component of F is  F_y =  F\ sin  \theta

   From the diagram , taking moment about the pivot we have  

                W_g  * 2 - F_y  * 1 =  0

Where W_g  is the weight of the gate evaluated as

             W_g  =  m_g * g =  100 * 9.8 =  980 \ N

=>        980 * 2 - Fsin(30)  * 1 =  0

=>         F = \frac{1960}{sin(30)}

=>      F = 3920 \ N

7 0
4 years ago
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Answer:

       

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3 years ago
If earth's mass were half its actual value but its radius stayed the same, the escape velocity of earth would be:________
siniylev [52]

If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

<h3>What is an escape velocity?</h3>

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

V_e=\sqrt{\dfrac{2GM}{r}}

Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

V_e=\sqrt{\dfrac{2GM}{r\times 2}}

V_e = \sqrt{\dfrac{GM}{r}}.

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be V_e = \sqrt{\dfrac{GM}{r}}.

To know more about escape velocity follow

brainly.com/question/14042253

#SPJ4

8 0
1 year ago
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dsp73

Answer:

true

Explanation:

The law of conservation of charge states that whenever electrons are transferred between objects, the total charge remains the same.

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