All but B, as on B an a can be factored out
Holding what.......? can u be more specific?
Answer:
x^87
Step-by-step explanation:
Multiplying x^22 and x^7 results in x^29.
Then we have:
(x^29)^3 = x^87
Recall that (a^b)^c = a^(bc) and that a^b*a^c = a^(b + c)
6/10 - 1/2...common denominator is 10
6/10 - 5/10 = 1/10 <==
