All categories

3 years ago

Drag equations to each row to show why the equation of a straight line is y = 3x, where 3 is the slope.

Mathematics

2 answers:

Vinvika [58]3 years ago

6 0

Answer:

there's the picture for the answer and your welcome :)

Step-by-step explanation:

a_sh-v [17]3 years ago

4 0

y/x = 3/1 Triangle 1 is similar to triangle 3

y = 3 x Multiply each side by x

You might be interested in

3. The population in the Northeast was 53,594,378 people in 2000 and 55,317,240 people in 2010. By about what percent did the po

Pepsi [2]

<span>The population in the Northeast was 53,594,378 people in 2000 and 55,317,240 people in 2010. By about what percent did the population change? Did the population grow or shrink?
C = 100*(55,317,240 - 53,594,378) / 53,594,378 = 3.2%. This is positive, so the population grew.</span>

6 0

3 years ago

HELP QUICKLY PLEASE HURRY!!!!!

BartSMP [9]

Answer:

it looks to be c

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

How do yall figure out how many people there are in a pie chart if it dont say and all it has is percents

fredd [130]

Change the percent to a decimal and then multiply

8 0

3 years ago

A certain intelligence test has an N(100, 100) distribution. To see whether intelligence is inherited, tests are given to the el

Anettt [7]

Answer:

Follows are the solution to the given choices:

Step-by-step explanation:

In choice a:

$\to \mu = 100$

In choice b:

$\to \mu \neq 100$

In choice c:

$\to \ pop \ average=100 \\\\ \to \ variance \ of \ pop = 100 \\\\\to pop \ \ \sigma = \sqrt {(!00)} \\$

= 10

$z= \frac{\bar x - \mu}{ \frac{\sigma}{\sqrt(n)}}\\\\$

$=\frac{(105-100)}{\frac{10}{ \sqrt(16)}}\\\\=\frac{(5)}{ \frac{10}{4}}\\\\=\frac{5}{ \frac{5}{2}}\\\\= \frac{10}{5}\\\\=2$

$\to p==2\times (1- \ righttail)\\\\\to \ righttail\ \ p = \text{NORM.S.DIST(2,TRUE)}$

$=0.977249868$

$\therefore \\P=2 \times (1-0.9772)\\\\P=0.0455\\\\P$

Null hypothesis to dismiss

Alternate solution assumptions embrace

There is really no valid proof at the 5% stage that

Knowledge is legacy

In choice d:

Possibly information such as this reflect a sample population with such a true p = 0.0455 meaning in the hypothesis

u is around 100.

11 +001

7 0

3 years ago

A cereal manufacturer produces cereal in boxes having a labeled weight of 15.7 ounces. Suppose that a random sample of 31 boxes

taurus [48]

Answer:

$t=\frac{16.14-15.7}{\frac{1.18}{\sqrt{31}}}=2.076$

$p_v =P(t_{(30)}>2.076)=0.0233$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the true mean for the weigths of cereal boxes is higher than 15.7 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=16.14$ represent the sample mean

$s=1.18$ represent the sample standard deviation

$n=31$ sample size

$\mu_o =15.7$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean is higher than 15.7 or no, the system of hypothesis would be:

Null hypothesis: $\mu \leq 15.7$

Alternative hypothesis: $\mu > 15.7$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{16.14-15.7}{\frac{1.18}{\sqrt{31}}}=2.076$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=31-1=30$

Since is a one side test the p value would be:

$p_v =P(t_{(30)}>2.076)=0.0233$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence toreject the null hypothesis, and we can conclude that the true mean for the weigths of cereal boxes is higher than 15.7 at 5% of signficance.

4 0

3 years ago