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3 years ago

7

Please help.

2 answers:

Alekssandra [29.7K]3 years ago

5 0

Matrices always go row x column.

Count the rows: 4

Count the columns: 3

The matrix is a 4 x 3 matrix

Zolol [24]3 years ago

3 0

The size of a matrix is defined by the number of rows and columns that it contains.

The dimensions of a matrix are the number of rows by the number of columns.

The number of rows and columns of a matrix, written in the form rows×columns.

The given Matrix has four rows and three columns,

The rows go side to side; the columns go up and down. "Row" and "column" are technical terms, and are not interchangeable.

Matrix dimensions are always given with the number of rows first, followed by the number of columns.

The matrix is a [4_] × [3_] matrix.

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A penny is 0.061 inchthick. wath is the valuee of the 6 in the thickness of a penny

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3 years ago

If x = 5 and y = x + 1 , find (x+y)+1/2<br> Pls quickly , ill mark branliest

elena-s [515]

Answer:

23/2

Step-by-step explanation:

If x = 5,

y = 5 + 1 = 6

(5+6) + 1/2 = 11 + 1/2 = 23/2

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3 years ago

Answer this volume based Question. I will make uh brainliest + 50 points

Harlamova29_29 [7]

Answer:

$\huge{\purple {r= 2\times\sqrt[3]3}}$

$\huge 2\times \sqrt [3]3 = 2.88$

Step-by-step explanation:

For solid iron sphere:
radius (r) = 2 cm (Given)

Formula for $V_{sphere}$ is given as:

$V_{sphere} =\frac{4}{3}\pi r^3$

$\implies V_{sphere} =\frac{4}{3}\pi (2)^3$

$\implies V_{sphere} =\frac{32}{3}\pi \:cm^3$

For cone:
r : h = 3 : 4 (Given)
Let r = 3x & h = 4x

Formula for $V_{cone}$ is given as:

$V_{cone} =\frac{1}{3}\pi r^2h$

$\implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)$

$\implies V_{cone} =\frac{1}{3}\pi (36x^3)$

$\implies V_{cone} =12\pi x^3\: cm^3$

It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
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$\implies 12x^3= \frac{32}{3}$

$\implies x^3= \frac{32}{36}$

$\implies x^3= \frac{8}{9}$

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$\implies x={\frac{2}{ \sqrt[3]{3^2}}}$

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$\implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}$

$\implies r=3\times 2(3)^{-\frac{2}{3}}$

$\implies r= 2\times (3)^{1-\frac{2}{3}}$

$\implies r= 2\times (3)^{\frac{1}{3}}$

$\implies \huge{\purple {r= 2\times\sqrt[3]3}}$
Assuming log on both sides, we find:

$log r = log (2\times \sqrt [3]3)$

$log r = log (2\times 3^{\frac{1}{3}})$

$log r = log 2+ log 3^{\frac{1}{3}}$

$log r = log 2+ \frac{1}{3}log 3$

$log r = 0.4600704139$

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$antilog(log r )= antilog(0.4600704139)$

$\implies r = 2.8844991406$

$\implies \huge \red{r = 2.88\: cm}$

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8 0

2 years ago

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Alex787 [66]

Answer:

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Step-by-step explanation:

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3 years ago

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earnstyle [38]

Answer:

0

a triangle's angles should add up to be 180 degrees. Three angles of 63's sum is 189

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3 years ago

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