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3 years ago

How do I do this problem I am stuck .

Mathematics

1 answer:

marta [7]3 years ago

7 0

1) Add 9 to both sides. On the left side of the equal sign it will cancel out. on the right side of the equal sign because it is now a different sign equation you subtract -193 from 9 which equals -184
2) now you are left with to= -184
to get the variable by itself you need to divide both sides by 4. on the left side of the equal sign you have p by itself now , on the right you divide -184 by 4 and your answer comes out to be p= -46
3) p= -46 is your final answer!

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sveticcg [70]

(a)The domain of the function is, $\rm x \geq -c^2 \ x\neq0$

(b)The given function is discontinuous at x=0.

<h3>What is the domain and range of a function?</h3>

Domain is the set of values for which the given function is defined. Range is the set of all values which the given function can output.

The standard function is;

$\rm f(x)= \frac{\sqrt{x+c^2-c} }{x} , c > 0$

The domain of the given function is found as;

$\rm x+c^2 \geq 0 \ x\neq 0 \\\\ x\geq-c^2 \ x\neq 0$

The domain of the function is,

$\rm x \geq -c^2 \ x\neq0$

To find the function is continuous or not, we have to find the continuity;

$\rm f(x) = \frac{\sqrt{ x+c^2-c}}{x} ,c > 0$

At x= 0 the function is undefined. So that the function is discontinuous at x=0.

Hence, The domain of the function is, $\rm x \geq -c^2 \ x\neq0$ and the function is discontinuous at x=0.

To learn more about domain, refer to the link:

brainly.com/question/20073127

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3 years ago

MARKING AS BRAINLIEST! LAST ATTEMPT! ) show ur work

matrenka [14]

Answer:

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$\sqrt{80} =\sqrt{(16)(5)} =4\sqrt{5)} \\3\sqrt{60} =3\sqrt{(15)(4)} =(3)(2)\sqrt{15} =6\sqrt{15}$

$-\sqrt{200} =-\sqrt{(100)(2)} =-10\sqrt{2}$

$4\sqrt{320} =4\sqrt{(64)(5)} =(4)(8)\sqrt{5} =32\sqrt{5}$

Hope this helps

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3 years ago

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katrin [286]

Answer:

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3 years ago

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Leona [35]

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