Answer:
Step-by-step explanation:
10 * sqrt(81/25 * -1) = 10 sqrt(81/25) * sqrt(-1) = 10 *9/5 * i
Answer:
<em>Perimeter = 20.6cm to 1dp = 20.60cm to 2dp</em>
<em>Area = Base = 8.6/2 = 4.3 x 4.069 = 17.5cm^2</em>
<em>Height is found 4.07 cos( 54.47deg) 5/8.6 = 4.069cm</em>
Step-by-step explanation:
<em>Right angle side triangle, sides </em>
<em>= MN =8.6cm </em>
<em>= NP=5cm </em>
<em>= PM=7cm </em>
<em>= 25sq + 49sq = 74sq</em>
<em>MN^2 =√74 = 8.60232526704 = 8.6cm</em>
<em>P = 8.6 + 5 + 7 = 20.6cm </em>
Answer: 2500
Explanation: I turned the I into a 1 and it turned into a 41 so I added 9+41 which is 50. Then I multiplied 50 by 50 because of the ^2 which gave me 2500. I’m assuming that you can put whatever number as a replacement for the I. I’m sorry if this answer isn’t right.
Answer:
22,40,62
Step-by-step explanation:
0+2=2 2+6=8 8+10=18
2 6 10 14 18 22 four in between
so you will add these numbers each time
18+14=22 22+18=40 40+22=62
Answer:
Tn = 2Tn-1 - Tn-2
Step-by-step explanation:
Before we can generate the recursive sequence, we need to find the nth term of the given sequence.
nth term of an AP is given as:
Tn = a+(n-1)d
If a17 = -40
T17 = a+(17-1)d = -40
a+16d = -40 ...(1)
If a28 = -73
T28 = a+(28-1)d = -73
a+27d = -73 ...(2)
Solving both equations simultaneously using elimination method.
Subtracting 1 from 2 we have:
27d - 16d = -73-(-40)
11d = -73+40
11d = -33
d = -3
Substituting d = -3 into 1
a+16(-3) = -40
a - 48 = -40
a = -40+48
a = 8
Given a = 8, d = -3, the nth term of the sequence will be
Tn = 8+(n-1) (-3)
Tn = 8+(-3n+3)
Tn = 8-3n+3
Tn = 11-3n
Given Tn = 11-3n and d = -3
Tn-1 = Tn - d... (3)
Tn-1 = 11-3n +3
Tn-1 = 14-3n
Tn-2 = Tn-2d...(4)
Tn-2 = 11-3n-2(-3)
Tn-2 = 11-3n+6
Tn-2 = 17-3n
From 3, d = Tn - Tn-1
From 4, d = (Tn - Tn-2)/2
Equating both common difference
(Tn - Tn-2)/2 = Tn - Tn-1
Tn - Tn-2 = 2(Tn - Tn-1)
Tn - Tn-2 = 2Tn-2Tn-1
2Tn-Tn = 2Tn-1 - Tn-2
Tn = 2Tn-1 - Tn-2
The recursive formula will be
Tn = 2Tn-1 - Tn-2
