starting from rest the road runner acceerates at 2.8m/s2 for 9.0seconfs how far does the road runner travels during the nine sec
1 answer:
Answer:
The roadrunner traveled <u>113.4 m</u> in 9 seconds.
Explanation:
Given:
Initial velocity of road runner (u) = 0 m/s 9 (Rest)
Acceleration of road runner (a) = 2.8 m/s²
Time taken by road runner (t) = 9.0 s
Now, displacement of the road runner can be determined using Newton's equation of motion.
In order to find the displacement, we need to use the equation of motion that relates displacement, initial velocity, acceleration and time.
Therefore, the equation of motion is given as:
Plug in the given values and solve for 'S'. This gives,
Therefore, the roadrunner traveled 113.4 m in 9 seconds.
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Answer:
Explanation:
This is a projectile motion problem. We will first separate the motion into x- and y-components, apply the equations of kinematics separately, then we will combine them to find the initial velocity.
The initial velocity is in the x-direction, and there is no acceleration in the x-direction.
On the other hand, there no initial velocity in the y-component, so the arrow is basically in free-fall.
Applying the equations of kinematics in the x-direction gives
For the y-direction gives
Combining both equation yields the y_component of the final velocity
Since we know the angle between the x- and y-components of the final velocity, which is 180° - 2.8° = 177.2°, we can calculate the initial velocity.