Answer:
Control of air–fuel ratio
Oxygen sensors tell the ECU whether the engine is running rich (too much fuel or too little oxygen) or running lean (too much oxygen or too little fuel) as compared to ideal conditions (known as stoichiometric).
Explanation:
Answer:
Explanation:
Each time the work done to raise a given mass is
here we know that
now we have
since it is just 25% of actual energy consumed as we know its efficiency is 25%
so we have total energy consumed in this way
now if it took N number of times so burn the fat of a pizza then
Answer:
is b and d hope id helpful
Explanation:
idk how to explain
Answer:
-360 kJ
Explanation:
Given:
m = 800 kg
v₀ = 30 m/s
v = 0 m/s
Δx = 75 m
Find: W
We can solve this using either forces or energy.
To use forces, first find the acceleration.
v² = v₀² + 2aΔx
(0 m/s)² = (30 m/s)² + 2a (75 m)
a = -6 m/s²
Then apply Newton's second law:
∑F = ma
F = (800 kg) (-6 m/s²)
F = -4800 N
Work is force times distance:
W = FΔx
W = (-4800 N) (75 m)
W = -360,000 J
W = -360 kJ
If you want to use energy instead:
work = change in energy
W = ΔKE
W = ½mv² − ½mv₀²
W = ½ (800 kg) (0 m/s)² − ½ (800 kg) (30 m/s)²
W = -360,000 J
W = -360 kJ
<span>The speed of water in pipe is given by:
V=0.408(Q/D^2)
V=speed
Q=flow rate
D=diameter of pipe
Hence, the speed of the water is inversely proportional to square of diameter
If the speed of water through 1-cm diameter is V
Then, speed of water through 0.5 cm diameter is
=V/[(1/2)^2)]
=V/(1/4)
=4V
Hence, compared to the speed of water in 1 cm pipe, the speed in the 1/2 cm pipe is four times.</span>
