1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
White raven [17]
3 years ago
5

The force required to start an object sliding across a uniform horizontal surface is larger than the force required to keep the

object sliding at a constant velocity. The magnitudes of the required forces are different in these situations because the force of kinetic friction
a) decreases as the speed of the object relative to the surface increases.

b)is greater than the force of static friction.

c) increases as the speed of the object relative to the surface increases.

d) is less than the force of static friction
Physics
1 answer:
taurus [48]3 years ago
3 0

The force required to start an object sliding across a uniform horizontal surface is larger than the force required to keep the object sliding at a constant velocity once it starts.

The magnitudes of the required forces are different in these situations because the force of kinetic friction is less than the force of static friction. <em>(d)</em>

You might be interested in
Plz plz answer quick...
Kruka [31]
I think it would increase because the lynx is a predator of the snowhare
3 0
3 years ago
What does the triad color scheme include?
Ainat [17]
I think it's C, three hues that are adjacent on the color wheel
3 0
3 years ago
Suppose you first walk 12.0 m in a direction 20? west of north and then 20.0 m in a direction 40.0? south of west. how far are y
Gnesinka [82]
The representation of this problem is shown in Figure 1. So our goal is to find the vector \overrightarrow{R}. From the figure we know that:

\left | \overrightarrow{A} \right |=12m \\ \\ \left | \overrightarrow{B} \right |=20m \\ \\ \theta_{A}=20^{\circ} \\ \\ \theta_{B}=40^{\circ}

From geometry, we know that:

\overrightarrow{R}=\overrightarrow{A}+\overrightarrow{B}

Then using vector decomposition into components:

For \ A: \\ \\ A_x=-\left | \overrightarrow{A} \right |sin\theta_A=-12sin(20^{\circ})=-4.10 \\ \\ A_y=\left | \overrightarrow{A} \right |cos\theta_A=12cos(20^{\circ})=11.27 \\ \\ \\ For \ B: \\ \\ B_x=-\left | \overrightarrow{B} \right |cos\theta_B=-20cos(40^{\circ})=-15.32 \\ \\ B_y=-\left | \overrightarrow{B} \right |sin\theta_B=-20sin(40^{\circ})=-12.85

Therefore:

R_x=A_x+B_x=-4.10-15.32=-19.42m \\ \\ R_y=A_y+B_y=11.27-12.85=-1.58m

So if you want to find out <span>how far are you from your starting point you need to know the magnitude of the vector \overrightarrow{R}, that is:
</span>
\left | \overrightarrow{R} \right |=&#10;\sqrt{R_x^2+R_y^2}=\sqrt{(-19.42)^2+(-1.58)^2}=\boxed{19.48m}

Finally, let's find the <span>compass direction of a line connecting your starting point to your final position. What we are looking for here is an angle that is shown in Figure 2 which is an angle defined with respect to the positive x-axis. Therefore:

</span>\theta_R=180^{\circ}+tan^{-1}(\frac{\left | R_y \right |}{\left | R_x \right |}) \\ \\ \theta_R=180^{\circ}+tan^{-1}(\frac{1.58}{19.42}) \\ \\ \theta_R=180^{\circ}+4.65^{\circ}=185.85^{\circ}


6 0
3 years ago
_____ occurs when a subject opens there eyes and devotes their attention to an object and the eeg rhythm changes to fast, irregu
slega [8]

Answer: B. Alpha block

Explanation:

3 0
3 years ago
Determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E].
sergeinik [125]

Answer:

3.44 metres

Explanation:

To determine the vector sum of the displacements Δd1 = 2.4 m [32° S of W]; Δd2 = 1.6 m [S]; and Δd3 = 4.9 m [27° S of E], resolve the given parameters into x - component and y - component.

Resolving into x - component

- 2.4cos32 + 4.9cos27 = 2.3306

Resolving into y - component

- 2.4sin32 - 4.9sin27 - 1.6 = - 2.553

The vector sum of the displacement will be

Sqrt( 2.3^2 + 2.6^2) =

Sqrt ( 11.81)

3.44 m

Therefore, the vector sum of the displacements is 3.44 metres

6 0
3 years ago
Other questions:
  • A beam of EMW in air strikes a sheet of a glass at 75 degrees with the normal in air. You observe that red light makes an angle
    13·1 answer
  • An object is pulled with 20 net of force to the right against a friction force of 10 net.what is the net force.in what direction
    6·1 answer
  • Wich sphere of the earth system includes snowfields ice caps and frozen ground
    10·1 answer
  • Only answer if you would send your eggplant
    11·1 answer
  • A block with mass m = 0.2 kg oscillates with amplitude A = 0.3 m at the end of a spring with force constant k = 12 N/m on a fric
    8·1 answer
  • 1)A ________ mirror can take far-away light and focus it so that the object being viewed, such as the moon or a star, can be see
    7·1 answer
  • An object is dropped and falls freely to the ground with an acceleration of g. If it is thrown upward at an angle instead, its a
    12·1 answer
  • Show that the units of g, previously given as N/kg, are also m/s^2.
    7·1 answer
  • How to brought people or myself out of sadness?
    8·1 answer
  • A man walks 7km East, and then 7 km West. What is the total distance the man walked? What is the displacement
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!