Question

How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh?

Answer 1

Answer:

The mass of the given number molecules of copper sulfate 88.98 g.

Explanation:

Number of copper sulfate molecules =  $3.36\times 10^{23}$

Moles of copper sulfate : x

Number of molecules = Moles$\times N_A$

$3.36\times 10^{23} =x\times 6.022\times 10^{23}$

x = 0.5579 moles

Mass of 0.5579 moles of copper sulfate:

$0.5579 mol\times 159.5 g/mol=13.38 g$

The mass of the given number molecules of copper sulfate 88.98 g.

Answer 2

Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
         ? g ------------------ 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g 

hope this helps!