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Effectus [21]
1 year ago
12

Answers for Chemistry A/Honors Chem A Unit 2 Test

Chemistry
1 answer:
Ivanshal [37]1 year ago
8 0

Intensive properties are useful for identifying a substance simply because these properties do not depend on the amount of sample, nor do they change according to conditions.

The correct answer choice which is a physical property of matter is boiling point.

Polymers are long chains of <u>molecules</u>

The method which I would use to separate two liquids with different boiling points is <u>distillation</u>

The particles are located in the nucleus of an atom are protons and neutrons

The type of molecular model which is used to represent very large molecules like proteins is ribbon diagram

The methods which is used to separate a mixture according to the size of the particles are filtration and chromatography

<h3>What is a mixture?</h3>

A mixture is a substance which contains two or more constituents which can easily be separated by physical means

So therefore, the methods which is used to separate a mixture according to the size of the particles are filtration and chromatography

Learn more about mixtures:

brainly.com/question/2331419

#SPJ1

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It is B, From the bottom of the pyramid to the top

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Which is a property of barium (Ba)?
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Why is an elements atomic mass not listed as a whole number in the periodic table
FinnZ [79.3K]

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They aren't listed as a whole number, because an atom's mass is not always a whole number. The mass differs between types of atoms as well.

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Read 2 more answers
The activation energy of an uncatalyzed reaction is 95kJ/mol. The addition of a catalyst lowers the activation energy to 55kJ/mo
notka56 [123]

Answer:

a) at 25°C the rate of reaction increases by a factor of 1,027*10^7

b) at 25°C the rate of reaction increases by a factor of 1,777*10^5

Explanation:

using the Arrhenius equation

k= ko*e^(-Ea/RT)

where

k= reaction rate

ko= collision factor

Ea= activation energy

R= ideal gas constant= 8.314 J/mol*K

T= absolute temperature

for the uncatalysed reaction

k1= ko*e^(-Ea1/RT)

for the catalysed reaction

k2= ko*e^(-Ea2/RT)

dividing both equations

k2/k1= e^(-(Ea2-Ea1)/RT)

a) at 25°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,027*10^7

therefore at 25°C , k2/k1 = 1,027*10^6

b) at 125°C

k2/k1 = e^(-(55kJ/mol-95kJ/mol)/(8.314J/mol*K*298K)* (1000J/kJ ) ) = 1,777*10^5

therefore at 125°C , k2/k1 = 1,777*10^5

Note:

when the catalysts is incorporated, the catalysed reaction and the uncatalysed one run in parallel and therefore the real reaction rate is

k real = k1 + k2 = k2 (1+k1/k2)

since k2>>k1 → 1+k1/k2 ≈ 1 and thus k real ≈ k2

6 0
3 years ago
Write a balanced chemical equation for the reaction of copper(II) sulfate and concentrated ammonia to produce teramine copper(II
Rudiy27

Answer:

CuSO4(aq) + 4NH3(aq) + nH2O→ [Cu(NH3)4H2On]S04(aq)

Explanation:

When the concentrated ammonia is added into the copper ions solution, a blue solid is formed. This blue solid is gelatinous.it consist of Cu(OH)2 in insoluble form. As more ammonia is added precipitate start to dissolve and [Cu(NH3)4]∧+2 is produce.

Net Ionic equation:

Cu∧+2 +4NH3 →  [Cu(NH3)4]∧+2

S04∧-2 are spectator ions.

Properties and uses of Tetraaminecopper(ll) sulfate:

1. It is solid compound.

2. Its color is dark blue.

3. It has ammonia like odor.

4. It is used to make the copper compounds and also used in the printing of fabric.

5. It is also used as pesticide.

3 0
2 years ago
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