Taylor series is 
To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have
f(x) = ln(x)
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.
.
Since we need to have it centered at 9, we must take the value of f(9), and so on.
f(9) = ln(9)
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.
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Following the pattern, we can see that for 
,
This applies for n ≥ 1, Expressing f(x) in summation, we have
Combining ln2 with the rest of series, we have
Taylor series is
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It will be 5 because 7x3 is 21, minus 26 to 21 is 5, won't be 7x4=28 and that's greater than 26
Answer:
{x,y}={8,5}
Step-by-step explanation:
12x + 12y = 156 4x + 6y = 62
We know that
if ∠WCR=49°
then
measure arc WR=49°-------> by central angle
circumference C=2*pi*r
for r=7 in
C=2*pi*7-----> 43.96 in
if 360°(full circle) has a length of----------> 43.96 in
49°---------------> x
x=49*43.96/360-----> x=5.98 in
alternative method
applying the formula
L=(∅/360°)*2*pi*r
where
∅ is the angle in degrees
r is the radius
L=(49°/360°)*2*pi*7------> L=5.98 in
the answer is
5.98 in
Answer:
CORRECT OPTION is (C) The flight will be late on one of the three days.
Step-by-step explanation:
The 7am flight from Dallas to Chicago is on time 75% of the time.
A spinner with four sections was created by Fran to simulate this scenario.
Since the 4 sections were equal, it means each section was 25% of the spinner.
3 sections were shaded. That implies 25 × 3 = 75% of the spinner was shaded area.
This coincides with the 75% probability that the flight is on time on a given day.
In other words, if the spinner's pointer lands on shaded area, the flight will be on time. If the pointer lands on an unshaded portion, the flight will be late.
Now Fran spun the spinner 3 times so she has 3 outcomes. The outcomes are:
- Shaded - Shaded - Unshaded
CORRECT OPTION is (C) The flight will be late on one of the three days.
