Answer:
d)Cells 1 and 2
Explanation:
In a voltaic cell, oxidation occurs at the anode and reduction occurs at the cathode. The half cell that function as anode or cathode in a voltaic cell depends strictly on the reduction potential of the metal ion/metal system in that half cell.
Examining the reduction potentials of the various metal ion/metal systems in the three half cells;
Cu= +0.34 V
Ni= -0.25 V
Zn= -0.76 V
Fe(Fe2+)= -0.44 V
Hence only Zn2+ has a more negative reduction potential than Fe2+. The more negative the reduction potential, the greater the tendency of the system to function as the anode. Thus iron half cell will function as anode in cells 1&2 as explained in the argument above.
The conversion of the fatty acid palmitate (C-16) to carbon dioxide via β-oxidation, the citric acid cycle and oxidative phosphorylation yield approximately <u>106 atp</u> equivalents.
The most prevalent kind of fatty acid with sixteen carbon atoms without carbon-carbon double bonds would be palmitic acid. There must be a maximum of seven cycles of beta-oxidation in order to totally degrade the fatty acid. 8 acetyl-CoA molecules, 7 NADH molecules, with 7 FADH2 molecules are produced as a result of this.
The primary enzyme, CAT-1, catalyzes the production of acylcarnitine carnitine, which provides the rate-limiting step in beta-oxidation.
Therefore, the conversion of the fatty acid palmitate (C-16) to carbon dioxide via β-oxidation, the citric acid cycle and oxidative phosphorylation yield approximately <u>106 atp</u> equivalents.
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Step (1):
Generation of electrophile: by the action of Lewis acid FeCl₃ on Cl₂ to serve as a source of Cl⁺ (Electrophile)
Step (2):
Addition of electrophile to form carbocation:
addition of electrophile to form C-Cl bond and form carbocation which is stabilized by resonance.
Step (3):
Loss of proton to re-form the aromatic ring by the action of FeCl₄⁻ which removes proton from carbon containing Cl and forming the aromatic ring again