This problem is requiring us to find the half life of the element. We can solve this problem by using the equation
as shown: A=Aoe^-(ln2/t)T where A is the final amount (5 kilogram), Ao is
the initial amount (40.0 kilogram), t is the half-life (required) and lastly T
time elapsed (4.0 years). Plug in the values in the equation and you should
get 1.33 years as the half life.
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Thee question is incomplete; the complete question is;
Which elements do not strictly follow the octet rule when they appear in the Lewis structure of a molecule?
Select one or more:
A: Chlorine
B: Carbon
C: Hydrogen
D: Sulfur
E: Fluorine
F: Oxygen
Answer:
chlorine
sulphur
Explanation:
The octet rule states that, for atoms to be stable, they must have eight electrons on their outermost shells.
This rule is not strictly followed by some elements such as sulphur and chlorine. The atoms of these elements can sometimes expand their octet by utilizing the d-orbitals found in the third principal energy level and beyond.
These leads to formation of compounds in which the central atom has more than eight electrons in its outermost shell.
Answer: Zn is an element and CuSO4 is an ionic compound.
Explanation: Got it right on EDG2020 :)
Answer:
V = 36.7L of 
Explanation:
1. Write the chemical reaction for the decomposition of sodium azide:

2. Find the number of moles of
produced by the decomposition of 71.4g of
:

3. Use the ideal gas equation to find the Volume of
occupied by 1.65 moles of
, at the temperature and pressure given by the problem:

Solving for V:

Converting the temperature from ◦C to K:
25◦C+273.15=298.15K
Replacing values:

V=36.7L of 