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Bezzdna [24]
3 years ago
13

Which of the following is an electrolyte?

Chemistry
2 answers:
Serggg [28]3 years ago
8 0
Electrolytes are inorganic substances that dissociate into ions in water. Examples of electrolytes include salts [for example, sodium chloride (NaCl) and magnesium chloride (MgCl2)] and ions [for example, potassium (K+)].
sleet_krkn [62]3 years ago
5 0

Answer:

option b Ca(NO3)2

Explanation:

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What is the density of and object that is 100 grams and has a volume of 5 cubic centimeters?
lesya [120]

Explanation:

Density of object = gram/volume

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3 years ago
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Where do glaciers come from
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3 years ago
You are given 100 g of a compound. The compound is composed of 37% hydrogen and 63% oxygen. How many grams of hydrogen are prese
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B is the best answer
4 0
3 years ago
Which of the elements below has the greatest electronegativity? <br> He <br> F <br> Fr <br> Rn
Law Incorporation [45]

F.
it's the greatest electron "hogger"
as you get closet to it, the stronger the electro negitivity.
He is halogen : they don't like to gain electrons. they are already stable.

Fr and Rn
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3 0
4 years ago
Read 2 more answers
Able 1 Cell Type Operating Cell Potential for Commercial Batteries, E (V) Lithium-iodine Zinc-mercury +2.80 +1.35 Table 2 Standa
IrinaK [193]

Answer:

During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.  ( B )

During the initial cell operation, the oxidation of iodine is  thermodynamically favorable but the oxidation of mercury is not. ( C )

Explanation:

<u>The major Differences between The Zinc mercury cell and Lithium-iodine cell are :</u>

During the initial cell operation, each reaction is thermodynamically favorable, but the larger operating potential of the lithium-iodine cell indicates that its cell reaction is more thermodynamically favorable.   and

During the initial cell operation, the oxidation of iodine is thermodynamically favorable but the oxidation of mercury is not.

Given the relationship below,

Δ G = -nFE

E = emf of cell ,  G = free energy.

This relationship shows that if E is positive the reaction will be thermodynamically favorable also if E is large it will increase the negativity of free energy  also From the question we can see that with the reduction of mercury the value of E is more positive and this shows that Mercury is thermodynamically unfavorable

8 0
3 years ago
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