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3 years ago

25.0 grams of Iron (III) oxide reacts with 30.0 grams of Silver sulfate in a double replacement reaction. Find the

Chemistry

1 answer:

VladimirAG [237]3 years ago

3 0

Answer:

iron

Explanation:

dued sshd sjdka dfdfvsdvsdvfdsbfdhh

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What is the final, balanced equation that is formed by combining these two half reactions?

lara31 [8.8K]

Answer: Balanced equation that is formed by combining these two half reactions is $Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O$ .

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, $Cu \rightarrow Cu^{2+} + 2e^{-}$

$NO^{-}_{3} + 2e^{-} + 2H^{+} \rightarrow NO^{-}_{2} + H_{2}O$

On cancelling the common species from both these half-reactions, the complete balanced equation will be as follows.

$Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O$

Thus, we can conclude that balanced equation that is formed by combining these two half reactions is $Cu + NO^{-}_{3} + 2H^{+} \rightarrow Cu^{2+} + NO^{-}_{2} + H_{2}O$ .

7 0

3 years ago

Sea water, a solution composed of a variety of salts dissolved in water. the salt is the

luda_lava [24]

In seawater, salt is the solute and water is the solvent.

4 0

3 years ago

What are the chemical formulas for..

andrezito [222]

S4O5
S3O
SeF6
N4S5
CCl9

All numbers should be subscripts

6 0

3 years ago

What do the atoms of a metal look like when they are in a body-centered cubic arrangement? A a cube with a ball stuck on each of

Natali [406]

<span>B) a cube with a ball stuck on each of its eight corners and one suspended at its center </span>

4 0

4 years ago

Calculate the change in enthalpy for the following reaction, using the bond enthalpy data provided below. (Note: you may round t

aliina [53]

Answer:

-514 kJ/mol

Explanation:

The bond enthalpy which is also known as bond energy can be defined as the amount of energy needed to split one mole of the stated bond. The change in enthalpy of a given reaction can be estimated by subtracting the sum of the bond energies of the reactants from the sum of the bond energies of the products.

For the given chemical reaction, the change in enthalpy of the reaction is:

Δ $H_{rxn} =$ [2(409) + 4(388) + 3(496) - 4(630) - 4(463)] kJ/mol = 818 + 1552 + 1488 - 2520 - 1852 = -514 kJ/mol

3 0

4 years ago