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gulaghasi [49]
3 years ago
6

Someone answer this question by me

Chemistry
2 answers:
Helga [31]3 years ago
8 0
Could you put the question here ? the link isn’t able to be copied :/
masha68 [24]3 years ago
7 0

Answer:

Uiiikjhb+2

Explanation:

I’m gonna swinggggggf

You might be interested in
Help ASAP!!!!!!!!!!!!!!!!!!!!!!!!!
BartSMP [9]

Answer:

ok      .

Explanation:            

3 0
3 years ago
I know the photo trash but i need answers for the top middle and last question please :)
Firlakuza [10]

Answer:

Middle: Self heating containers are really expensive but are useful because they are easy to use, portable, and can be recycled, unlike a camp stove which is not as easily moved.

Explanation:

i neeed a better image for the first an last boo<3

6 0
3 years ago
A. Identify which sets of quantum numbers are valid for an electron. Each set is ordered (n,ℓ,mℓ,ms).
Butoxors [25]

Answer:

a. Values are - (1) 3,1,-1,1/2        (2) 2,1,-1,-1/2       (3) 3,0,0,1/2    (4) 4,3,3,-1/2

(5) 3,2,2,1/2

b. Order be- I > Sn > Xe

Explanation:

a.

Valid quantum numbers are -

'l' value should be less than 'n' value and 'ml' value should be '-l' to 'l'

'ml' value should not more than 'l' or 'n'.

Values are -

3,1,-1,1/2

2,1,-1,-1/2

3,0,0,1/2

4,3,3,-1/2

3,2,2,1/2

b.

Given that-

I [Kr]4d¹⁰5s²5p⁵

Sn [Kr]4d¹⁰5s²5p²

Xe [Kr]4d¹⁰5s²5p⁶

Order be-

I > Sn > Xe

Xe is least because it is completely filled outer shell (5s²5p⁶

4 0
3 years ago
A gas occupies 3.56 L at 1.00 atm. What will be the volume of this gas if the pressure becomes 4.00 atm?
coldgirl [10]

Answer:

0.890 L

Explanation:

P1V1 = P2V2

P1 = 1.00 atm

V1 = 3.56 L

P2 = 4.00 atm

V2 = ?

Solve for V2 --> V2 = P1V1/P2

V2 = (1.00 atm)(3.56 L) / (4.00 atm) = 0.890 L

8 0
4 years ago
To investigate the reactivity of metals a student uses four metals. Each time they added 1 g of the metal to 25 cm³ of sulfuric
Mazyrski [523]

Answer:

Volume of the sulfuric acid (25cm³), same mass of each metal (1g)

Explanation:

In an experiment, the CONTROL VARIABLE also known as constant is the variable that is kept unchanged for all groups in an experiment. This is done in order not to influence the outcome of the experiment.

In this case, students are trying to investigate the reactivity of four different metals. They added 1 g of each metal to 25cm³ of sulfuric acid and recorded the temperature change. Based on the explanation of control variable above, the VOLUME OF SULFURIC ACID (25cm³) and the MASS OF EACH METAL (1g) are the CONTROL VARIABLES because they are the same or unchanged in this experiment.

5 0
3 years ago
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