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Nady [450]
3 years ago
11

- 6x + 5y - 2x + 4 =

Mathematics
1 answer:
pychu [463]3 years ago
5 0

Answer:

-8x + 5y + 4

Step-by-step explanation:

- 6x + 5y - 2x + 4 Group like terms

-6x - 2x + 5y + 4

=  - 8x + 5y + 4

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One angle of a right triangle measures 61°. What is the measure of the other acute angle?
svetlana [45]
The other answer is 29 degrees because 90 for right angle and 61 for one angle is 151 then subtract 180 (for the Triangle Sum theory) minus 151 then it’s 29 degrees
8 0
3 years ago
SSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
hjlf
Yes between those answers the answer of S will be S let me tell you why, when you carry over the s of subtracting s the answer of s is s so it may also possibly be s^48
8 0
3 years ago
a company decided to increase the size of the box for the packaging of their alcohol products. the length of the original packag
Igoryamba

Answer:

The answer is below

Step-by-step explanation:

a company decided to increase the size of the box for the packaging of their alcohol products. the length of the original packaging box was 40 cm longer than its width and the height 12 cm, volume was at most 4800 cm3. Suppose the length of the new packaging box is still 40cm longer than its width and the height is 12cm, what mathematical statement would represent the volume of the new packaging box?​

Solution:

Let the width of the box be x cm.

The length of the box is 40 cm longer than the width, therefore the length of the box = x + 40

The height of the box = 12 cm

The volume of the box can be gotten from the formula:

Volume = length × width × height

Substituting:

Volume = (x + 40) × (x) × 12

Volume = 12x(x + 40)

Therefore the volume of the new box is 12x(x + 40)

8 0
3 years ago
Cosx+1/sin^3x=cscx/1-cosx
ANTONII [103]
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

 </span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).

 </span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.

 </span>
<span>I hope this helps! </span>
8 0
4 years ago
A pole that is 3 m tall casts a shadow that is 1.74 m long at the same time a nearby building casts a shadow that is 50.75 m lon
bija089 [108]
87.5

Tall. /. Shadow
3 / 1.74=. X /. 50.75
Cross multiply
152.25= 3x
Divide by 3
X= 87.5
4 0
3 years ago
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