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Finger [1]
3 years ago
6

WHO IS CORRECT? LIAM or TEHYA?

Mathematics
2 answers:
horsena [70]3 years ago
5 0

Answer: Both Liam and Tehya

Step-by-step explanation:

ale4655 [162]3 years ago
4 0

Answer:

<h2>Liam is right.</h2>

Step-by-step explanation:

The transformation that demonstrate the congruence between these two triangles is the given one by Liam:

\triangle ABC can be reflected over the y-axis to create \triangle EFD

You can get this answer by observing the given graph. You can realize that one triangle is a reflection of the other across y-axis, because when this happens, the x-coordinates are changed by their opposite. There you can see that

x = -7 is changed to x' = 7

x = -3 is changed to x' = 3

x = -2 is changed to x' = 2

Therefore, the right transformation is the reflection accross y-axis given by Liam, he's right.

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1/16

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A square of an even number is always even.<br>True or false?<br>​
aksik [14]

Answer:

Mostly likely it's True

Step-by-step explanation:

5 0
2 years ago
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Question: Find Angle S<br><br> SOMEONE PLEASE HELP WILL GIVE BRAINLEST!
fenix001 [56]

Answer: 45

Step-by-step explanation:

S is 45 (labelled on the diagram)

4 0
3 years ago
Formulate the situation as a system of inequalities. (Let x represent the number of goats the farmer can raise and y represent t
Firdavs [7]

Answer: He can raise up to 40 goats and 100 llamas.

Step-by-step explanation:

Hi, to answer this question we have to write system of equations with the information given:

The space each goat needs (4) multiplied by the number of goats (x); plus The space each llama needs (10) multiplied by the number of llamas must be less or equal to the acre land available (800)

4x +10y ≤ 800 (acres)

The amount of veterinary care (in $) each  goat needs (110) multiplied by the number of goats (x); plus The  amount of veterinary care   each llama needs (88) multiplied by the number of llamas (y)must be less or equal to the Rancher's budget.(14520)

110x +88y ≤ 14,520 (cost)

Multiplying the first equation by 27.5, and subtracting the second equation to the first one:

110x + 275y ≤22,000

-

110x +88y ≤ 14,520

____________

187y ≤ 7480

y ≤ 7480/187

y ≤ 40

Replacing y in the first equation

4x +10(40) ≤ 800

4x +400 ≤ 800

4x ≤ 800-400

4x ≤ 400

x ≤ 400/4

x ≤ 100

5 0
3 years ago
An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberr
Veseljchak [2.6K]

Answer:

<em>The calculated value |t| = 2.375 > 2.1009  at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>Alternative hypothesis is accepted</em>

<em>The extra carbonation of cola results in a higher average compression strength</em>

<u><em /></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given data</em>

<em>First sample size (n₁) = 10 </em>

<em>mean of the first sample(x₁⁻) = 537</em>

<em>standard deviation of the first sample (S₁) = 22</em>

<em>second sample size (n₂) = 10 </em>

<em>mean of the second sample (x₂⁻) = 559</em>

<em>standard deviation of the second sample (S₂) = 17</em>

<u><em>Step(ii)</em></u><em>:-</em>

<u><em>Null hypothesis : H₀:</em></u><em>- The extra carbonation of cola results in a lower average compression strength</em>

<u>Alternative Hypothesis :H₁</u>

<em>The extra carbonation of cola results in a higher average compression strength</em>

<u><em>Step(iii)</em></u><em>:-</em>

<em>By using student's t -test for difference of means</em>

<u><em>Test statistic</em></u>

<em>       </em>t = \frac{x^{-} _{1}-x^{-} _{2}  }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} }  } )}<em />

<em>  where </em>

<em>     </em>S^{2}  = \frac{n_{1}S^{2} _{1} + n_{2} S_{2} ^{2}  }{n_{1}+n_{2} -2 }<em />

<em>    </em>S^{2}  = \frac{10(22)^{2}  + 10 (17) ^{2}  }{10+10 -2 } = \frac{ 7730}{18} = 429.4<em />

<em>    </em>t = \frac{537-559 }{\sqrt{429.4 (\frac{1}{10 }+\frac{1}{10 }  } )}<em />

<em>   t =  -2.375</em>

<em>|t| = |-2.375| = 2.375</em>

<em>Degrees of freedom</em>

<em>γ = n₁+n₂ -2 = 10+10-2 =18</em>

<em />t_{\frac{\alpha }{2} ,n-1}=t_{(\frac{0.05}{2} ,18)} = t_{(0.025,18)}}=2.1009<em />

<em>The calculated value |t| = 2.375 > 2.1009  at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>Alternative hypothesis is accepted</em>

<u><em>Final answer:-</em></u>

<em>The extra carbonation of cola results in a higher average compression strength</em>

<u><em /></u>

<em />

<em> </em>

<em />

5 0
3 years ago
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