Question

Please help with answers and showing work

Answer 1

Answer:

1:c

let x be the distance

12^2=10^(2) + x^(2)

x=6.6332

2.D

length of 2->3 and 2->1 is 90ft, they are perpendicular

by using Pythagorus theorem

the diagonal of the square = square root of the sum of 90^2 +90^2

=127.279ft

3.B

12^2  -6^2 = 10.39ft

Step-by-step explanation: