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attashe74 [19]
3 years ago
7

Please help with answers and showing work

Mathematics
1 answer:
avanturin [10]3 years ago
4 0

Answer:

1:c

let x be the distance

12^2=10^(2) + x^(2)

x=6.6332


2.D

length of 2->3 and 2->1 is 90ft, they are perpendicular

by using Pythagorus theorem

the diagonal of the square = square root of the sum of 90^2 +90^2

=127.279ft


3.B

12^2  -6^2 = 10.39ft


Step-by-step explanation:


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This is your typical algebra question where you are looking for an unknown value given some information. The information can be set up as:
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3 years ago
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Answer:

D:Spring A is 3 m longer than spring B because 15 – 12 = 3.

Step-by-step explanation:

In this question, you should remember the Hooke's Law in physics.

The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.

The mathematical expression for this law is

F=-kx

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F= force applied on the spring

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The question will need you to calculate the extension on the springs A and B then compare the values obtained.

<u>In spring A</u>

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To find the extension x apply the expression;

F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x

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Force, F=60N and spring constant , k=5N/m

To find the extension x apply the same expression

F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x

Here the extension on the spring is 12 m

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The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m

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