"He starts both trains at the same time. Train A returns to its starting point every 12 seconds and Train B returns to its starting point every 9 seconds". Basically, what you need to do is find the least common multiple. The least common multiple of 12 and 9 is 36, so the least amount of time, in seconds, that both trains will arrive at the starting points at the same time is 36 seconds.
Answer:
The answer would be 10. Multiply 10 by 10 you'll get 100.
Step-by-step explanation:
For a half- life, the formula is
A(t) = A0(0.5)^( t / t_0.5)
where A(t) is the amount of substance at time t
A0 is the initial amount of subtance
t_0.5 is the time it will reduce its amount to half
t is the time
substitute the given to the formula
A(t) = 100(0.5)^( t/6 )
so the decay factor is 0.5^( t/6 )
Answer:
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Step-by-step explanation:
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Answer:
B' is at (2.76,-4.9)
Equation of CC' is 11.38x+4.55y= -31.86
or at its slope-intercept form:
y= (-11.38x - 31.86)/4.55
Step-by-step explanation: