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777dan777 [17]
3 years ago
12

FIND THE VALUEOF THE VARIBLE AND FILL THE BLANK.

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
4 0

Answer:

f = 2

g = 8

h = -9

k = 40

m = 1

Step-by-step explanation:

Equation 1:

23f - 17 = 29

Add 17 to both sides. This undoes the -17.

23f = 29 + 17

Add 17 to 29 to get 46.

23f = 46

Divide both sides by 23. This undoes the multiplication by 23.

f = 46/23

Divide 46 by 23 to get 2.

f = 2

Equation 2:

2(3g + 4) = 56

Divide both sides by 2. This undoes the multiplication by 2.

3g + 4 = 56/2

Divide 56 by 2 to get 28.

3g + 4 = 28

Subtract 4 from both sides. This undoes the +4.

3g = 28 - 4

Subtract 4 from 28 to get 24.

3g = 24

Divide both sides by 3. This undoes the multiplication by 3.

g = 24/3

Divide 24 by 3 to get 8.

g = 8

Equation 3:

h + 9 = 0

Subtract 9 from both sides. This undoes the +9.

h = 0 - 9

Any number subtracted from 0 gives its negation.

h = -9

Equation 4

3(k - 8) = 96

Divide both sides by 3. This undoes the multiplication by 3.

k - 8 = 96/3

Divide 96 by 3 to get 32.

k - 8 = 32

Add 8 to both sides. This undoes the -8.

k = 32 + 8

Add 8 to 32 to get 40.

k = 40

Equation 5:

5m - 5 = 0

Add 5 to both sides. This undoes the -5

5m = 0 + 5

Anything plus 0 gives itself.

5m = 5

Divide both sides by 5. This undoes the multiplication by 5

m = 5/5

Anything divided by itself gives you 1.

m = 1

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For this case we have the following distributions given:

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0.4           10%    4%

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Part 1

The expected value is given by this formula:

E(X)=\sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%

Part 2

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Part 3

We can calculate the second moment first with the following formula:

E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1

And the variance would be given by:

Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89

And the deviation would be:

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Part 4

We can calculate the second moment first with the following formula:

E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8

And the variance would be given by:

Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56

And the deviation would be:

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