Answer:
As shown in picture, this circle has radius 1.5 and passes (0, 1.5)
=> According to the general form of equation of circle that has radius r and passes (a, b): (x - a)^2 + (y - b)^2 = r^2, we have:
x^2 + (y - 1.5)^2 = 1.5^2
<=>
x^2 + (y - 1.5)^2 = 2.25
Hope this helps!
:)
Answer:
There were 76 childrens and 14 adults.
Step-by-step explanation:
Since the group has a total of 90 children and adults, then the sum of the number of adults with the number of children must be equal to 90 as shown below:
children + adults = 90
Since the total cost for their tickets was 548 then the number of children multiplied by the price of their ticket summed by the number of adults multiplied by the price of their ticket must be equal to that. We have:
5*children + 12*adults = 548
With these two equations we have a system of equations shown below:
children + adults = 90
5*children + 12*adults = 548
In order to solve this we will multiply the first equation by -5, and sum both equations we have:
-5*children - 5*adults = -450
5*children + 12*adults = 548
7*adults = 98
adults = 98/7 = 14
children + 14 = 90
children = 90 - 14 = 76
There were 76 childrens and 14 adults.
Answer:
x = 9 or x = 0 or x = -2
Step-by-step explanation:
Solve for x:
3 x^3 - 21 x^2 - 54 x = 0
The left hand side factors into a product with four terms:
3 x (x - 9) (x + 2) = 0
Divide both sides by 3:
x (x - 9) (x + 2) = 0
Split into three equations:
x - 9 = 0 or x = 0 or x + 2 = 0
Add 9 to both sides:
x = 9 or x = 0 or x + 2 = 0
Subtract 2 from both sides:
Answer: x = 9 or x = 0 or x = -2
Answer:
No solution.
Step-by-step explanation:
Step 1: Write inequality
3(x - 2) + 1 ≥ x + 2(x + 2)
Step 2: Solve for <em>x</em>
- Distribute: 3x - 6 + 1 ≥ x + 2x + 4
- Combine like terms: 3x - 5 ≥ 3x + 4
- Add 5 to both sides: 3x ≥ 3x + 9
- Subtract 3x on both sides: 0 ≥ 9
Here we see that the statement is false. Therefore, you cannot solve for the inequality.
