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2 years ago

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RATE MY SINGING: what you know about rolling down in the deep when your brain goes numb you call that mental freeze if I gave yo

u all my love would that make you happy yeah yeahhh eyahh

2 answers:

Maurinko [17]2 years ago

7 0

Answer:

wow!

Step-by-step explanation:

Bezzdna [24]2 years ago

3 0

100 out of 10 it was amazing

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Since the number of members attending is 40, you can eliminate 17 as a possible answer, as it is smaller than 40. You can also eliminate 240 because 40 members is 60%, so the answer must be less than 80. You are now left with 67 and 73.

It is (a) because 40 divided by 67 = 0.597. 0.597 x 100 = 59.7% which is rounded to 60% of the club

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A 12 foot ladder is placed against the side of the building. The base of the ladder is placed at an angle of 68° with the ground

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3 years ago

Did you get the answer to this question

Harlamova29_29 [7]

The anser is all of the above please make brainlyleist

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2 years ago

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Find the slope intercept form of the equation of the line that’s has the given properties (1 , 3) m=1/4

Helga [31]

Answer:

y = 1/4x + 11/4

Step-by-step explanation:

Given the slope, m = 1/4, and the point, (1, 3):

We can substitute these values into the slope-intercept form, y = mx + b, in order to solve for the y-intercept.

The y-coordinate (b) of the point, (0, <em>b </em>) is the <u>y-intercept </u>of the line where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0.

y = mx + b

3 = 1/4(1) + b

3 = 1/4 + b

Subtract 1/4 from both sides:

3 - 1/4 = 1/4 - 1/4 + b

11/4 = b

The y-coordinate, b, of the y-intercept is 11/4.

Therefore, the slope-intercept form is: y = 1/4x + 11/4

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2 years ago

Lamaj is rides his bike over a piece of gum and continues riding his bike at a constant rate time = 1.25 seconds the game is at

Hitman42 [59]

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.

a. If the diameter of the wheel is 68 cm, write an equation that models the height of the gum in centimeters above the ground at any time, t, in seconds.

b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?

c. When are the first and second times the gum reaches a height of 12 cm?

Answer:

Step-by-step explanation:

a)

We are being told that:

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation that models the height of the gum in centimeters above the ground at any time, t, in seconds. can be written as:

$\mathbf {y = 34cos (\pi (t-1.25))+34}$

where;

y = is the height of the gum at a given time (t) seconds

34 = amplitude of the motion

the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.

$\mathbf{ \pi}$ = the period of the graph

1.25 = maximum vertical height stretched by 1.25 m to the horizontal

b) From the equation derived above;

if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .

So;

$\mathbf {y = 34cos (\pi (15.6-1.25))+34}$

$\mathbf {y = 34cos (\pi (14.35))+34}$

$\mathbf {y = 34cos (45.08)+34}$

$\mathbf{y = 58.01}$

Thus, the gum is at 58.01 cm from the ground at t = 15.6 seconds.

c)

When are the first and second times the gum reaches a height of 12 cm

This indicates the position of y; so y = 12 cm

From the same equation from (a); we have :

$\mathbf {y = 34 cos(\pi (t-1.25))+34}$

$\mathbf{12 = 34 cos ( \pi(t-1.25))+34}$

$\dfrac {12-34}{34} = cos (\pi(t-1.25))$

$\dfrac {-22}{34} = cos(\pi(t-1.25))$

$2.27 = (\pi (t-1.25)$

t = 2.72 seconds

Similarly, replacing cosine in the above equation with sine; we have:

$\mathbf {y = 34 sin (\pi (t-1.25))+34}$

$\mathbf{12 = 34 sin ( \pi(t-1.25))+34}$

$\dfrac {12-34}{34} = sin (\pi(t-1.25))$

$\dfrac {-22}{34} = sin (\pi(t-1.25))$

$-0.703 = (\pi(t-1.25))$

t = 2.527 seconds

Hence, the gum will reach 12 cm first at 2.527 sec and second time at 2.72 sec.

7 0

2 years ago