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e-lub [12.9K]
2 years ago
15

Sorry that the pic is upside down ANSWER IT PLSNO LINKS​

Mathematics
1 answer:
ki77a [65]2 years ago
7 0
The answers to that question is 75 degreey
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PLEASE HELP
konstantin123 [22]
The length of the minor arc AB is 6.3cm
7 0
3 years ago
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substitute the given values into the formula & solve for the unknown variable A = bh ; A = 12 , b =4
Sauron [17]

A = bh

12 = 4 × h [substitute A for 12 and b for h]

12 / 4 = h

3 = h

Therefore, h equals 4.



7 0
3 years ago
Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36}
Brums [2.3K]

1st quartile: 11

median: 38.50000

3rd quartile: 45

<h3>According to the given information:</h3>
  • Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
  • There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
  • 6,7,15,36, or the left-most half of the data, make up the sample.
  • The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
  • 41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
  • The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
  • The biggest value deviates 10.5 from the median (49-38.5)

Measure descriptive statistics

1st quartile: 11

median: 38.50000

3rd quartile: 45

To know more about quartile visit:

brainly.com/question/8737601

#SPJ4

I understand that the question you are looking for is :

2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions.  {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5  median 11  third quartile 10.5 the difference of the largest value and the median 45

7 0
2 years ago
What digit can be in the ones place of a number that has 5 as a factor?
Sedaia [141]
0 and 5 can be in the one's place of a number that has 5 as a factor.
8 0
3 years ago
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write an equation of the perpendicular bisector of the line segment whose endpoints are (-1,1) and (7,-5)
gladu [14]
Find midpoint of segment.
(-1,1), (7,-5)
x= \frac{-1+7}{2}=3,y= \frac{1+(-5)}{2}=-2

Find slope of line which passes through (-1,1) and (7,-5).
m= \frac{-5-1}{7-(-1)}= \frac{-6}{8}=- \frac{3}{4}

The slope of perpendicular line is negative reciprocal value of m.
m_{\perp}=- \frac{1}{m} =- \frac{1}{- \frac{3}{4} } = \frac{4}{3}

Write quation of line which slope is \frac{4}{3} and passes throug the point (3,-2).
m=\frac{4}{3},x_1=3,y_1=-2&#10;\\y-y_1=m(x-x_1)&#10;\\&#10;\\y-(-2)=\frac{4}{3}(x-3)&#10;\\&#10;\\y+2=\frac{4}{3}x-\frac{8}{3}&#10;\\&#10;\\3y+6=4x-8&#10;\\4x-3y-14=0

3 0
3 years ago
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