Write and graph an equation that is perpendicular to the equation x-3y=6 and through point (2,-3)
2 answers:
Answer:
The answer to your question is y = -3x + 3
Step-by-step explanation:
See the graph below
Data
Perpendicular to x - 3y = 6
Point = (2, -3)
Process
1.- Find the slope of the line given
x - 3y = 6
-3y = -x + 6
y = -1/-3x + 6/-3
y = 1/3x - 2
slope = 1/3
2.- Find the slope of the new line
slope = -3
3.- Find the equation of the new line
y + 3 = -3(x - 2)
y + 3 = -3x + 6
y = -3x + 6 - 3
y = -3x + 3
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Explanation:
sum -- the result of addition: 5x+1
term -- a constant, variable, or product of a constant and one or more variables. In the more general sense, a term is any part of the expression that can be considered by itself. An example is 5x
product -- the result of multiplication: 9(5x+1), where 9 is multiplied by the sum (5x+1)
factor -- part of a product: x
quotient -- the result of division: 9(5x+1)÷3
coefficient -- a constant, or the constant that multiplies the variables in a term: 5
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<em>Additional comment</em>
The way this is written, there will be the tendency to think of 3y as a term in the same sense that 5x is a term. That would be incorrect. The Order of Operations has you interpret this expression as ...