Write and graph an equation that is perpendicular to the equation x-3y=6 and through point (2,-3)
2 answers:
Answer:
y = mx + b is slope-intercept form of the linear equation.
y - y1 = m(x - x1) is point-slope form of the linear equation.
Ax + By = C (A ≥ 0) is standard form of the linear equation.
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....
1
y – 5 = —— (x + 1)
3
1 1
y = —— x + —— + 5
3 3
1 16
(1) y = —— x + ——
3 3
Step-by-step explanation:
Answer:
The answer to your question is y = -3x + 3
Step-by-step explanation:
See the graph below
Data
Perpendicular to x - 3y = 6
Point = (2, -3)
Process
1.- Find the slope of the line given
x - 3y = 6
-3y = -x + 6
y = -1/-3x + 6/-3
y = 1/3x - 2
slope = 1/3
2.- Find the slope of the new line
slope = -3
3.- Find the equation of the new line
y + 3 = -3(x - 2)
y + 3 = -3x + 6
y = -3x + 6 - 3
y = -3x + 3
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Answer:
25/81
Step-by-step explanation:
The probability of randomly selecting two oranges = (number of oranges in the bowl / total number of fruits in the bowl) x (number of oranges in the bowl / total number of fruits in the bowl)
total number of fruits in the bowl = 5 + 4 = 9
5/9 x 5/9 = 25/81
The formula for a slope is
. Inserting those values into the equation, we get (12 - 9) / (8 - (-4)) = 3/12 =
1/4
D. Points on a line do not have a quadrant.
So h is 3x
To evaluate 4y/x for x=8 and y=0 we shall have:
. Inserting those values into the equation, we get (12 - 9) / (8 - (-4)) = 3/12 = 1/4