Question

What is the work required to deflect a linear spring (k=32 kN/m) by 120 cm?

Answer 1

Answer:

the work done by the linear spring will be equal to 23.04 k J

Explanation:

given,

k = 32 k N /m

deflected spring = 120 cm

                            = 1.2 m

work done by spring can be calculate as

                          = $\dfrac{1}{2}kx^2$

                          = $\dfrac{1}{2}\times 32 \times 1.2^2$

                          = 23.04 k J

hence, the work done by the linear spring will be equal to 23.04 k J