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alex41 [277]
3 years ago
5

Based on the pattern, what are the next two terms of the sequence? 9,94,916,964,9256,... A. 91024,94096 B. 9260,91028 C. 9260,92

64 D. 91024,91028
Engineering
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

The answer is "Option A".

Explanation:

Series:

9, 94, 916, 964, 9256, ........

Solving the above series:

\to  9\\ \to  9(4) =94\\\to 9 (4^2) = 9(16) =916\\\to 9 (4^3) = 9(64) =964\\\to 9 (4^4) = 9(256) =9256\\\to 9 (4^5) = 9(1024) =91024\\\to 9 (4^6) = 9(4096) =94096\\

So, the series is:  9, 94, 916, 964, 9256, 91024, 94096, .................

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The correct area in sq. Inches and sq. Feet is: Select one: a. 966.76 sq. Inches and 8.056 sq. Feet b. 96.676 sq. Inches and 8.0
kogti [31]

Answer:

c. 96.676 sq. Inches and 0.671 sq. Feet

Explanation:

From the list of the given option, we are told to chose the correct area in sq. inches that correspond to sq. Feet.

If we recall from the knowledge of our conversion  table that,

1 sq feet = 144 sq inches

Then, let's confirm if the option were true.

a.  966.76 sq. Inches and 8.056 sq. Feet

Assuming

if 1 sq feet = 8.056

in sq inches, we have ( 8.056 × 144 ) sq inches

= 1160.064 sq. inches

So, 1160.064 sq. inches is equal to 8.056 sq. Feet. Then option 1 is wrong

b. 96.676 sq. Inches and 8.056 sq. Feet

if 1 sq feet = 8.056

in sq inches, we have ( 8.056 × 144 ) sq inches

= 1160.064 sq. inches

So, 1160.064 sq. inches is equal to 8.056 sq. Feet. Then option 2 is wrong/

c. 96.676 sq. Inches and 0.671 sq. Feet

if 1 sq feet = 0.671

in sq inches, we have ( 0.671 × 144 ) sq inches

=  96.624 sq. Inches which is closely equal to 96.676 sq. Inches

Therefore, this is the correct answer as it proves that 96.676 sq. Inches = 0.671 sq. Feet

8 0
3 years ago
An automated transfer line is to be designed. Based on previous experience, the average downtime per occurrence = 5.0 min, and t
IRINA_888 [86]

Answer:

a) 28 stations

b) Rp = 21.43

E = 0.5

Explanation:

Given:

Average downtime per occurrence = 5.0 min

Probability that leads to downtime, d= 0.01

Total work time, Tc = 39.2 min

a) For the optimum number of stations on the line that will maximize production rate.

Maximizing Rp =minimizing Tp

Tp = Tc + Ftd

=  \frac{39.2}{n} + (n * 0.01 * 5.0)

= \frac{39.2}{n} + (n * 0.05)

At minimum pt. = 0, we have:

dTp/dn = 0

= \frac{-39.2}{n^2} + 0.05 = 0

Solving for n²:

n^2 = \frac{39.2}{0.05} = 784

n = \sqrt{784} = 28

The optimum number of stations on the line that will maximize production rate is 28 stations.

b) Tp = \frac{39.2}{28} + (28 * 0.01 * 5)

Tp = 1.4 +1.4 = 2.8

The production rate, Rp =

\frac{60min}{2.8} = 21.43

The proportion uptime,

E = \frac{1.4}{2.8} = 0.5

3 0
3 years ago
What tools are used to build a watch tower PLEASE HELP ME​
harkovskaia [24]

Answer:

The trunks were all cut at the same lenght, 9 Carolingian feet, easier to carry away and to build. The construction was built by a team of four people, using traditional tools such as a hand saw, clamp, gimlet, Catalan type axe, wood hammer, chisel, two-handed wood saw, heavy wood hammer and metal wedges.

Explanation:

8 0
3 years ago
A rigid tank contains 3 kg of water initially at 43.97% quality and at a temperature of 120°C. The water is heated until it reac
makkiz [27]

Explanation: see attachment below

6 0
3 years ago
A 20 kg mass is thrown from the ground to a height of 50 m. (a) find the kinetic energy of the mass at this height. (b) find the
horrorfan [7]

Answer:

(a) 0 kJ

(b) 9.81 kJ

(c) 31.32 m/s

Explanation:

(a)

From the law of conservation of energy, energy can only be transformed from one state to another. At a height of 50 m, all the kinetic energy is converted to potential energy hence KE=0

(b)

Potential energy, PE=mgh where m is the mass, g is acceleration due to gravity and h is the height

Substituting 50 m for h and 20 Kg for m, taking g as 9.81 then

PE=20*9.81*50=9810 J=9.81 kJ

(c)

Relating the equation of potential energy to the equation of kinetic energy, which is 0.5mv^{2}

mgh=0.5mv^{2} where v is the velocity of the mass

v=\sqrt {2gh}

Substituting 50 m for h and taking g as 9.81 then

v=\sqrt {2*9.81*50}=31.32091953\approx 31.32 m/s

3 0
3 years ago
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