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hjlf
3 years ago
12

The ratio of boys to girls in the class was 2 to 3. If there were 18 girls in the class, how many students were in the class

Engineering
1 answer:
iren2701 [21]3 years ago
4 0
37 students in the class
18 Girls and 19 Boys
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provides steady-state operating data for a solar power plant that operates on a Rankine cycle with Refrigerant 134a as its worki
Vaselesa [24]

Answer:

hello some parts of your question is missing attached below is the missing part ( the required fig and table )

answer : The solar collector surface area = 7133 m^2

Explanation:

Given data :

Rate of energy input to the collectors from solar radiation = 0.3 kW/m^2

percentage of solar power absorbed by refrigerant = 60%

Determine the solar collector surface area

The solar collector surface area = 7133 m^2

attached below is a detailed solution of the problem

8 0
3 years ago
In primary processing their are 3 different steps, what are the steps?
Nana76 [90]

Answer:

Primary processing involves cutting, cleaning, packaging, storage and refrigeration of raw foods to ensure that they are not spoilt before they reach the consumer.

8 0
3 years ago
A glass plate is subjected to a tensile stress of 40 MPa. If the specific surface energy is 0.3 J/m2 and the modulus of elastici
Alika [10]

Answer:

The maximum length of a surface flaw is 8.24 μm

8.24 μm

Explanation:

Given that:

The modulus of elasticity E = 69 GPa

The specific surface energy \delta_s = 0.3 J/m²

The length of the surface flaw "a" = ??

From the theory of the brittle fracture;

\sigma _c = \bigg (  \dfrac{2E \delta_s}{\pi a}  \bigg )^{1/2}

Making a the subject of the formula; we have:

a = \bigg (  \dfrac{2 \times E \times \delta_s}{\pi \sigma _c ^2}  \bigg )

a= \bigg (  \dfrac{2 \times 69*10^9 \times 0.3}{\pi (40*10^6)^2}  \bigg )

a = 8.24 × 10⁻⁶ m

a = 8.24 μm

Thus; the maximum length of a surface flaw is 8.24 μm

3 0
3 years ago
Column arrays: Transpose a row array Construct a row array countValues with elements 1 to endValue, using the double colon opera
White raven [17]

Answer:

Matlab code with step by step explanation and output results are given below

Explanation:

We have to construct a Matlab function that creates a row vector "countValues" with elements 1 to endValue. That means it starts from 1 and ends at the value provided by the user (endValue).  

function countValues = CreateArray(endValue)

% Here we construct a row vector countValues from 1:endValue

     countValues = 1:endValue;

% then we transpose this row vector into column vector

     countValues = countValues';

 end

Output:

Calling this function with the endValue=11 returns following output

CreateArray(11)

ans =

    1

    2

    3

    4

    5

    6

    7

    8

    9

   10

   11

Hence the function works correctly. It creates a row vector then transposes it and makes it a column vector.

7 0
3 years ago
Compute the fundamental natural frequency of the transverse vibration of a uniform beam of rectanqular cross section, with one e
marshall27 [118]

Answer:

The natural angular frequency of the rod is 53.56 rad/sec

Explanation:

Since the beam is free at one end and fixed at the other hence the beam is a cantilevered beam as shown in the attached figure

We know that when a unit force is placed at the end of a cantilever the displacement of the free end is given by

\Delta x=\frac{PL^3}{3EI}

Hence we can write

P=\frac{3EI\cdot \Delta x}{L^3}

Comparing with the standard spring equation F=kx we find the cantilever analogous to spring with k=\frac{3EI}{L^3}

Now the angular frequency of a spring is given by

\omega =\sqrt{\frac{k}{m}}

where

'm' is the mass of the load

Thus applying values we get

\omega _{beam}=\sqrt{\frac{\frac{3EI}{L^{3}}}{Area\times density}}

\omega _{beam}=\sqrt{\frac{\frac{3\times 20.5\times 10^{10}\times \frac{0.1\times 0.3^3}{12}}{5.9^{3}}}{0.3\times 0.1 \times 7830}}=53.56rad/sec

8 0
3 years ago
Read 2 more answers
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