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Elina [12.6K]
3 years ago
9

Kevin is 2 times as old as Gaberiela, 12 years ago, Kevin was 6 times as old as Gaberiela

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

Kevin was 2 times as old as Gabriela 12 years ago then Kevin was 6 times as old as Gabriela so now Kevin should be 36 years old because if you divide 12 by 2 it's gonna give you 6 so then he was 6 times old as Gabriela so now he's 36 years old.

Step-by-step explanation:

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Answer:

Step-by-step explanation:

tanx=27/38

take the inverse...

tan^-1(27/38)

≈35.4 degrees

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3 years ago
Find an equation for the graph
Elanso [62]

Answer:

y=6^x+0.612 - 4

Step-by-step explanation:

x = -4 ---> horizontal asymptote

m = 6 ---> use points (0, -1) and (1, 5)

Parent function of the graph: y=b^x

Our equation: y=6^x

Add alterations:

  1. Reflections = N/A
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Final equation: y=6^x+0.612 - 4


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2 years ago
PLS HELP ASAP I AM TIMED DON TGUESS EXPLAIN ANSWER
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A bus company is replacing all the old seats in its buses with new ones. The company owns 15 buses and each bus has 22 seats. It
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Answer:

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Which of the following sets of lengths can Sean use to make a right triangle?
Aleks [24]

Answer:

{8 cm, 15 cm, 17 cm}

Step-by-step explanation:

we know that

The length sides of a right triangle must satisfy the Pythagoras Theorem

so

c^2=a^2+b^2

where

c is the greater side (the hypotenuse)

a and b are the legs (perpendicular sides)

<u><em>Verify each case</em></u>

case 1) we have

{5 cm, 15 cm, 18 cm}

substitute in the formula

18^2=5^2+15^2

324=250 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 2) we have

{6 cm, 12 cm, 16 cm}

substitute in the formula

16^2=8^2+12^2

256=208 ----> is not true

therefore

Sean cannot make a right triangle with this set of lengths

case 3) we have

{5 cm, 13 cm, 15 cm}

substitute in the formula

15^2=5^2+13^2

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case 4) we have

{8 cm, 15 cm, 17 cm}

substitute in the formula

17^2=8^2+15^2

289=289 ----> is true

therefore

Sean can make a right triangle with this set of lengths

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